Mechanism Lab Open the app

Oxidative alkene cleavage

Lemieux-Johnson oxidation

How the Lemieux-Johnson oxidation works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

Open the interactive version

In short. A 3-step mechanism. Typical reagents: Alkene, OsO₄ (cat., 1–5 mol%), NaIO₄ (≥ 4 equiv.), 2,6-lutidine (optional). Conditions: Dioxane/H₂O or THF/H₂O, 25 °C. Bonds formed: two C=O; IO₃⁻; bonds broken: C=C (σ and π); C–C of the diol. Stereochemistry: Alkene geometry lost; α-stereocentres retained. Rate and selectivity: Osmylation is fast; NaIO₄ turns over Os(VI) → Os(VIII).

At a glance

ReagentsAlkene, OsO₄ (cat., 1–5 mol%), NaIO₄ (≥ 4 equiv.), 2,6-lutidine (optional)
Solvent / conditionsDioxane/H₂O or THF/H₂O, 25 °C
Bonds formedtwo C=O; IO₃⁻
Bonds brokenC=C (σ and π); C–C of the diol
StereochemistryAlkene geometry lost; α-stereocentres retained
Rate / selectivityOsmylation is fast; NaIO₄ turns over Os(VI) → Os(VIII)

Step 1: OsO₄ adds across the alkene

+[3+2]OsOOOOOOsOOO1 · OSO₄ ADDS ACROSS THE ALKENEcyclohexeneC₆H₁₀NUCLEOPHILEosmium tetroxideOXIDANTcyclic osmate esterINTERMEDIATEConcerted syn addition: both C–O bonds form on the same face; Os(VIII) → Os(VI).

OsO₄ adds across the alkene in a concerted [3+2] cycloaddition, giving a cyclic osmate ester, the same first step as Upjohn dihydroxylation.

Step 2: Diol, then periodate ester

H₂O++– 2 H₂OOOsOOOOHOHOsOOOHOHOHOHOIOOOOIOOOO2 · DIOL, THEN PERIODATE ESTERcyclic osmate esterINTERMEDIATEcis-1,2-diolC₆H₁₂O₂INTERMEDIATEOs(VI) osmateBYPRODUCTcis-1,2-diolC₆H₁₂O₂SUBSTRATEperiodateOXIDANTcyclic periodate esterINTERMEDIATENaIO₄ also oxidises Os(VI) back to OsO₄, so only a catalytic amount of osmium is needed.

Hydrolysis gives a syn-1,2-diol and reduced osmium(VI). NaIO₄ then does two jobs at once: it cleaves the diol through a cyclic periodate ester, and it reoxidizes the osmium back to OsO₄, so only a catalytic amount of the toxic metal is needed.

Step 3: C–C cleavage to two carbonyls

C–C cleavage+OIOOOOOOOIOO3 · C–C CLEAVAGE TO TWO CARBONYLScyclic periodate esterSUBSTRATEhexanedialC₆H₁₀O₂PRODUCTiodateBYPRODUCTEach former alkene carbon ends as C=O; no ozone, no ozonide, room temperature.

The C–C bond breaks, giving two carbonyl compounds: an aldehyde or ketone from each former alkene carbon. Unlike ozonolysis the reaction runs at room temperature with no ozone generator or explosive ozonide, which is why it is a convenient alternative.

Abbreviations and terms

THF
Tetrahydrofuran. Cyclic ether solvent; its oxygen lone pairs solvate Li⁺/Mg²⁺ so organometallics stay dissolved and reactive.
OsO4
Osmium tetroxide. Adds syn across alkenes to give diols (via a cyclic osmate ester).

How it compares with related reactions

Lemieux-Johnson oxidationKMnO₄ oxidation of an alkeneOzonolysis
ReagentsAlkene, OsO₄ (cat., 1–5 mol%), NaIO₄ (≥ 4 equiv.), 2,6-lutidine (optional)cold dilute KMnO₄, OH⁻ (diol); hot conc. KMnO₄ (cleavage)1) O₃ 2) Me₂S or Zn/AcOH (reductive workup)
ConditionsDioxane/H₂O or THF/H₂O, 25 °C0–5 °C, basic, vs. heat, acidCH₂Cl₂ or MeOH, –78 °C
StereochemistryAlkene geometry lost; α-stereocentres retainedSyn addition (cis diol) in cold conditionsAlkene geometry is lost
Rate / selectivityOsmylation is fast; NaIO₄ turns over Os(VI) → Os(VIII)Cycloaddition fast; Mn(VII) → Mn(V) → MnO₂Fast, even at –78 °C; ozonide is explosive, never isolated

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Lemieux-Johnson oxidation?

Alkene, OsO₄ (cat., 1–5 mol%), NaIO₄ (≥ 4 equiv.), 2,6-lutidine (optional). Conditions: Dioxane/H₂O or THF/H₂O, 25 °C.

Which bonds are formed and which are broken?

Formed: two C=O; IO₃⁻. Broken: C=C (σ and π); C–C of the diol.

What is the stereochemical outcome?

Alkene geometry lost; α-stereocentres retained

What controls the rate or the selectivity?

Osmylation is fast; NaIO₄ turns over Os(VI) → Os(VIII)

Study guides that help with this reaction

Related mechanisms

Step through it interactively, then test yourself in Quiz