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Alkene oxidation — syn-diol or cleavage

KMnO₄ oxidation of an alkene

How the KMnO₄ oxidation of an alkene works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: cold dilute KMnO₄, OH⁻ (diol); hot conc. KMnO₄ (cleavage). Conditions: 0–5 °C, basic, vs. heat, acid. Bonds formed: two C–O (syn diol) or C=O; bonds broken: C=C π (and C–C on cleavage). Stereochemistry: Syn addition (cis diol) in cold conditions. Rate and selectivity: Cycloaddition fast; Mn(VII) → Mn(V) → MnO₂.

At a glance

Reagentscold dilute KMnO₄, OH⁻ (diol); hot conc. KMnO₄ (cleavage)
Solvent / conditions0–5 °C, basic, vs. heat, acid
Bonds formedtwo C–O (syn diol) or C=O
Bonds brokenC=C π (and C–C on cleavage)
StereochemistrySyn addition (cis diol) in cold conditions
Rate / selectivityCycloaddition fast; Mn(VII) → Mn(V) → MnO₂

Step 1: [3+2] cycloaddition

+OMnOOOOMnOOO1 · [3+2] CYCLOADDITIONcyclohexeneC₆H₁₀NUCLEOPHILEpermanganateMnO₄⁻OXIDANTcyclic manganate(V) esterINTERMEDIATEBoth C–O bonds form on one face in a concerted step; Mn(VII) is reduced to Mn(V).

The alkene's π electrons attack manganese in a concerted [3+2] cycloaddition, exactly like the OsO₄ mechanism in Sharpless dihydroxylation, forming a five-membered cyclic manganate ester across both alkene carbons.

Step 2: Cold, basic: hydrolysis to syn diol

+H₂O+ MnO₂OMnOOOOHOHOH2 · COLD, BASIC: HYDROLYSIS TO SYN DIOLcyclic manganate esterINTERMEDIATEhydroxideHO⁻NUCLEOPHILEcis-cyclohexane-1,2-diolC₆H₁₂O₂PRODUCTMn–O bonds break, not C–O, so the syn stereochemistry is kept.

Under cold, dilute, basic conditions, hydrolysis of this manganate ester simply releases a 1,2-diol with syn stereochemistry — the same outcome as OsO₄ dihydroxylation, just with a cheaper, more common oxidant.

Step 3: Hot, conc.: oxidative cleavage

hot conc. KMnO₄H₃O⁺++OOOOH₂3 · HOT, CONC.: OXIDATIVE CLEAVAGE2-methyl-1-buteneC₅H₁₀SUBSTRATEbutan-2-oneC₄H₈OPRODUCTcarbon dioxideCO₂BYPRODUCTwaterH₂OBYPRODUCTFully substituted C=C carbon → ketone; =CH₂ carbon is over-oxidised to CO₂ + H₂O.

Under hot, concentrated conditions, the initially formed diol is oxidized further, cleaving the C–C bond entirely — a disubstituted alkene carbon becomes a ketone, while a monosubstituted (terminal) alkene carbon is oxidized all the way to CO₂ and water. This harsher cleavage pathway is a classic way to determine an alkene's substitution pattern from its oxidation products.

Abbreviations and terms

H2
Hydrogen gas. Reductant for catalytic hydrogenation.
OsO4
Osmium tetroxide. Adds syn across alkenes to give diols (via a cyclic osmate ester).
KMnO4
Potassium permanganate. Strong oxidant: diols (cold, basic) or cleavage (hot).

How it compares with related reactions

KMnO₄ oxidation of an alkeneLemieux-Johnson oxidationBaeyer-Villiger oxidation of a ketone
Reagentscold dilute KMnO₄, OH⁻ (diol); hot conc. KMnO₄ (cleavage)Alkene, OsO₄ (cat., 1–5 mol%), NaIO₄ (≥ 4 equiv.), 2,6-lutidine (optional)mCPBA or CH₃CO₃H (peracid)
Conditions0–5 °C, basic, vs. heat, acidDioxane/H₂O or THF/H₂O, 25 °CCH₂Cl₂, 25 °C; cat. acid helps
StereochemistrySyn addition (cis diol) in cold conditionsAlkene geometry lost; α-stereocentres retainedRetention at the migrating carbon
Rate / selectivityCycloaddition fast; Mn(VII) → Mn(V) → MnO₂Osmylation is fast; NaIO₄ turns over Os(VI) → Os(VIII)Migratory aptitude: tert > cyclohexyl ≈ sec > Ph > prim > Me

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the KMnO₄ oxidation of an alkene?

cold dilute KMnO₄, OH⁻ (diol); hot conc. KMnO₄ (cleavage). Conditions: 0–5 °C, basic, vs. heat, acid.

Which bonds are formed and which are broken?

Formed: two C–O (syn diol) or C=O. Broken: C=C π (and C–C on cleavage).

What is the stereochemical outcome?

Syn addition (cis diol) in cold conditions

What controls the rate or the selectivity?

Cycloaddition fast; Mn(VII) → Mn(V) → MnO₂

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