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Alkene synthesis — silicon-based

Peterson olefination

How the Peterson olefination works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: Me₃SiCH₂⁻ (from Me₃SiCH₂Cl, Mg or n-BuLi), ketone/aldehyde. Conditions: THF, –78 → 25 °C; base (KH) or acid (H₂SO₄, BF₃) for elimination. Bonds formed: C–C; C=C; Si–O; bonds broken: C=O π; C–Si; C–O. Stereochemistry: Basic: syn elimination; acid: anti elimination (opposite alkene geometry). Rate and selectivity: Alkoxide addition fast; elimination driven by Si–O bond (≈ 110 kcal/mol).

At a glance

ReagentsMe₃SiCH₂⁻ (from Me₃SiCH₂Cl, Mg or n-BuLi), ketone/aldehyde
Solvent / conditionsTHF, –78 → 25 °C; base (KH) or acid (H₂SO₄, BF₃) for elimination
Bonds formedC–C; C=C; Si–O
Bonds brokenC=O π; C–Si; C–O
StereochemistryBasic: syn elimination; acid: anti elimination (opposite alkene geometry)
Rate / selectivityAlkoxide addition fast; elimination driven by Si–O bond (≈ 110 kcal/mol)

Step 1: α-Silyl carbanion adds to C=O

+SiOδ⁻OSi1 · Α-SILYL CARBANION ADDS TO C=O(trimethylsilyl)methyl anionC₄H₁₁Si⁻NUCLEOPHILEacetoneC₃H₆OELECTROPHILEβ-silyl alkoxideC₇H₁₇OSi⁻INTERMEDIATESilicon stabilises the adjacent carbanion (α-effect).

An alpha-silyl carbanion (stabilized by adjacent silicon) attacks a ketone's carbonyl carbon, forming a β-silyl alkoxide — the silicon analog of the Wittig's betaine intermediate.

Step 2: Syn elimination of Me₃SiO⁻

syn elimination+OSiSiO2 · SYN ELIMINATION OF ME₃SIO⁻β-silyl alkoxideC₇H₁₇OSi⁻INTERMEDIATEisobuteneC₄H₈PRODUCTtrimethylsilanolateC₃H₉OSi⁻BYPRODUCTO⁻ attacks Si (4-membered 1,2-oxasiletanide-like TS); O and Si leave together.

Under basic conditions, this alkoxide undergoes a syn-periplanar elimination, with oxygen and the adjacent silyl group leaving together as the new C=C π bond forms.

Step 3: Si–O bond formation drives it

H₂O+SiOSiOH3 · SI–O BOND FORMATION DRIVES ITtrimethylsilanolateC₃H₉OSi⁻BYPRODUCTtrimethylsilanolC₃H₁₀OSiBYPRODUCTalkeneC₄H₈PRODUCTAcid-promoted elimination (anti) gives the opposite alkene geometry from base (syn).

The driving force is the exceptionally strong Si–O bond formed in the trimethylsilanolate byproduct — this reaction gives clean alkene geometry that's controllable by choosing acidic vs. basic elimination conditions.

Abbreviations and terms

THF
Tetrahydrofuran. Cyclic ether solvent; its oxygen lone pairs solvate Li⁺/Mg²⁺ so organometallics stay dissolved and reactive.
n-BuLi
n-Butyllithium. Very strong base/nucleophile (pKa of butane ≈ 50); deprotonates alkynes and does lithium–halogen exchange.
KH
Potassium hydride. Stronger/faster relative of NaH.
BF3
Boron trifluoride. Lewis acid (usually as the Et₂O complex).
H2SO4
Sulfuric acid. Strong acid and dehydrating agent.
TS
Transition state. The highest-energy point on the pathway between two minima; it cannot be isolated.

How it compares with related reactions

Peterson olefinationJulia-Kocienski olefinationHorner-Wadsworth-Emmons (HWE) reaction
ReagentsMe₃SiCH₂⁻ (from Me₃SiCH₂Cl, Mg or n-BuLi), ketone/aldehyde1-phenyl-1H-tetrazol-5-yl (PT) sulfone, KHMDS (or NaHMDS, LiHMDS), aldehydePhosphonate ester (EtO)₂P(O)CH₂CO₂Et, NaH or NaOMe, aldehyde
ConditionsTHF, –78 → 25 °C; base (KH) or acid (H₂SO₄, BF₃) for eliminationTHF or DME, –78 °C → 25 °CTHF or DME, 0–25 °C
StereochemistryBasic: syn elimination; acid: anti elimination (opposite alkene geometry)Highly E-selective (anti-adduct, then anti elimination)Strong E-selectivity (trans)
Rate / selectivityAlkoxide addition fast; elimination driven by Si–O bond (≈ 110 kcal/mol)One-pot; Smiles shift and elimination are fast after additionAldehyde addition rate-limiting; water-soluble phosphate easily removed

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Peterson olefination?

Me₃SiCH₂⁻ (from Me₃SiCH₂Cl, Mg or n-BuLi), ketone/aldehyde. Conditions: THF, –78 → 25 °C; base (KH) or acid (H₂SO₄, BF₃) for elimination.

Which bonds are formed and which are broken?

Formed: C–C; C=C; Si–O. Broken: C=O π; C–Si; C–O.

What is the stereochemical outcome?

Basic: syn elimination; acid: anti elimination (opposite alkene geometry)

What controls the rate or the selectivity?

Alkoxide addition fast; elimination driven by Si–O bond (≈ 110 kcal/mol)

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