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Sulfone-based alkene synthesis — classic

Julia-Lythgoe olefination

How the Julia-Lythgoe olefination works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: 1) PhSO₂CH₂R, n-BuLi; R′CHO 2) Ac₂O 3) Na(Hg), MeOH. Conditions: THF, –78 °C; then Na/Hg, –20 °C. Bonds formed: C–C; C=C; PhSO₂⁻; AcO⁻; bonds broken: C=O; C–S; C–O. Stereochemistry: E-alkene regardless of sulfone diastereomer (radical/anion equilibration). Rate and selectivity: Single-electron transfer to the sulfone is key.

At a glance

Reagents1) PhSO₂CH₂R, n-BuLi; R′CHO 2) Ac₂O 3) Na(Hg), MeOH
Solvent / conditionsTHF, –78 °C; then Na/Hg, –20 °C
Bonds formedC–C; C=C; PhSO₂⁻; AcO⁻
Bonds brokenC=O; C–S; C–O
StereochemistryE-alkene regardless of sulfone diastereomer (radical/anion equilibration)
Rate / selectivitySingle-electron transfer to the sulfone is key

Step 1: Sulfonyl carbanion adds to the aldehyde

+SOOROROSOO1 · SULFONYL CARBANION ADDS TO THE ALDEHYDEmetalated phenyl sulfoneC₈H₉O₂S⁻NUCLEOPHILEaldehydeELECTROPHILEβ-alkoxysulfoneINTERMEDIATE

A metalated phenyl sulfone's carbanion attacks an aldehyde's carbonyl carbon in an ordinary nucleophilic addition, forming a β-alkoxysulfone.

Step 2: Acylate; electron transfer cleaves C–S

Ac₂ONa(Hg), MeOH2 e⁻+ROSOOROOSOOROOSOOROOOSO2 · ACYLATE; ELECTRON TRANSFER CLEAVES C–SalkoxideNUCLEOPHILEβ-acetoxysulfoneINTERMEDIATEβ-acetoxysulfoneSUBSTRATEβ-acetoxy carbanionANIONbenzenesulfinateC₆H₅O₂S⁻LEAVING GROUPRadical anion fragments to PhSO₂⁻ and an alkyl radical, which takes a second electron.

The alkoxide is converted to a good leaving group (commonly as an acetate ester), and reduction with sodium amalgam or a similar single-electron reductant triggers a radical-anion elimination — electrons add to the sulfone, which fragments, expelling both the sulfinate and the acetate leaving group together.

Step 3: β-Elimination of acetate gives the E-alkene

E1cB+ROOROO3 · Β-ELIMINATION OF ACETATE GIVES THE E-ALKENEβ-acetoxy carbanionANION(E)-alkenePRODUCTacetateC₂H₃O₂⁻LEAVING GROUP

This reductive elimination forms the new alkene directly, favoring the E-isomer — the classic Julia olefination predates the milder Julia-Kocienski variant covered earlier, which was developed specifically to avoid this reaction's harsh reductive elimination step.

Abbreviations and terms

R
R group. Any carbon substituent (alkyl, aryl…) whose identity does not matter for the mechanism.
THF
Tetrahydrofuran. Cyclic ether solvent; its oxygen lone pairs solvate Li⁺/Mg²⁺ so organometallics stay dissolved and reactive.
MeOH
Methanol. Polar protic solvent (also a nucleophile in solvolysis).
n-BuLi
n-Butyllithium. Very strong base/nucleophile (pKa of butane ≈ 50); deprotonates alkynes and does lithium–halogen exchange.
Ac2O
Acetic anhydride. Acetylating agent.
E1cB
Elimination, unimolecular conjugate base. Deprotonation first to a carbanion, then loss of the leaving group.

How it compares with related reactions

Julia-Lythgoe olefinationJulia-Kocienski olefinationPeterson olefination
Reagents1) PhSO₂CH₂R, n-BuLi; R′CHO 2) Ac₂O 3) Na(Hg), MeOH1-phenyl-1H-tetrazol-5-yl (PT) sulfone, KHMDS (or NaHMDS, LiHMDS), aldehydeMe₃SiCH₂⁻ (from Me₃SiCH₂Cl, Mg or n-BuLi), ketone/aldehyde
ConditionsTHF, –78 °C; then Na/Hg, –20 °CTHF or DME, –78 °C → 25 °CTHF, –78 → 25 °C; base (KH) or acid (H₂SO₄, BF₃) for elimination
StereochemistryE-alkene regardless of sulfone diastereomer (radical/anion equilibration)Highly E-selective (anti-adduct, then anti elimination)Basic: syn elimination; acid: anti elimination (opposite alkene geometry)
Rate / selectivitySingle-electron transfer to the sulfone is keyOne-pot; Smiles shift and elimination are fast after additionAlkoxide addition fast; elimination driven by Si–O bond (≈ 110 kcal/mol)

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Julia-Lythgoe olefination?

1) PhSO₂CH₂R, n-BuLi; R′CHO 2) Ac₂O 3) Na(Hg), MeOH. Conditions: THF, –78 °C; then Na/Hg, –20 °C.

Which bonds are formed and which are broken?

Formed: C–C; C=C; PhSO₂⁻; AcO⁻. Broken: C=O; C–S; C–O.

What is the stereochemical outcome?

E-alkene regardless of sulfone diastereomer (radical/anion equilibration)

What controls the rate or the selectivity?

Single-electron transfer to the sulfone is key

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