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Alkene synthesis — ylide chemistry

Wittig reaction: ylide + acetaldehyde → alkene

How the Wittig reaction works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: Ph₃P=CH₂ (ylide, from Ph₃P⁺CH₃ Br⁻ + n-BuLi); acetaldehyde. Conditions: THF, 0 °C → 25 °C; anhydrous, inert atmosphere. Bonds formed: C=C π; P=O (very strong, ~130 kcal/mol); bonds broken: C=O π; P–C. Stereochemistry: Unstabilised ylides: Z-alkene; stabilised: E-alkene. Rate and selectivity: Driven by the strong P=O bond of Ph₃P=O.

At a glance

ReagentsPh₃P=CH₂ (ylide, from Ph₃P⁺CH₃ Br⁻ + n-BuLi); acetaldehyde
Solvent / conditionsTHF, 0 °C → 25 °C; anhydrous, inert atmosphere
Bonds formedC=C π; P=O (very strong, ~130 kcal/mol)
Bonds brokenC=O π; P–C
StereochemistryUnstabilised ylides: Z-alkene; stabilised: E-alkene
Rate / selectivityDriven by the strong P=O bond of Ph₃P=O

Step 1: Ylide carbon attacks C=O

+PPh₃Oδ⁻PPh₃O1 · YLIDE CARBON ATTACKS C=OmethylenetriphenylphosphoraneYLIDEacetaldehydeC₂H₄OELECTROPHILEbetaine (zwitterion)INTERMEDIATENucleophilic C attacks the carbonyl carbon; shown stepwise for clarity.

A phosphorus ylide carries a carbanion-like carbon stabilized by the adjacent, electropositive phosphorus. That carbon is strongly nucleophilic and attacks the electrophilic carbonyl carbon of the aldehyde.

Step 2: Oxaphosphetane forms

PPh₃OPPh₃O2 · OXAPHOSPHETANE FORMSbetaineINTERMEDIATEoxaphosphetaneINTERMEDIATEFour-membered P–C–C–O ring: new C–C and P–O bonds.

This forms a strained four-membered ring — an oxaphosphetane — as the new C–C bond and a P–O bond form together.

Step 3: Retro-[2+2]: alkene + Ph₃P=O

+PPh₃OPPh₃O3 · RETRO-[2+2]: ALKENE + PH₃P=OoxaphosphetaneINTERMEDIATEpropeneC₃H₆PRODUCTtriphenylphosphine oxideBYPRODUCTThe ring fragments; the strong P=O bond is the driving force.

The ring collapses in a retro-[2+2]-like step: the C–C bond stays, a new C=C π bond forms, and triphenylphosphine oxide is ejected. The net effect is installing an alkene exactly where the carbonyl used to be.

Abbreviations and terms

THF
Tetrahydrofuran. Cyclic ether solvent; its oxygen lone pairs solvate Li⁺/Mg²⁺ so organometallics stay dissolved and reactive.
n-BuLi
n-Butyllithium. Very strong base/nucleophile (pKa of butane ≈ 50); deprotonates alkynes and does lithium–halogen exchange.
PPh3
Triphenylphosphine. Nucleophilic phosphine; forms very strong P=O bonds, driving Wittig, Appel and Mitsunobu reactions.
TPPO
Triphenylphosphine oxide. The thermodynamic sink of Wittig/Mitsunobu/Appel reactions.

How it compares with related reactions

Wittig reactionHorner-Wadsworth-Emmons (HWE) reactionJulia-Kocienski olefination
ReagentsPh₃P=CH₂ (ylide, from Ph₃P⁺CH₃ Br⁻ + n-BuLi); acetaldehydePhosphonate ester (EtO)₂P(O)CH₂CO₂Et, NaH or NaOMe, aldehyde1-phenyl-1H-tetrazol-5-yl (PT) sulfone, KHMDS (or NaHMDS, LiHMDS), aldehyde
ConditionsTHF, 0 °C → 25 °C; anhydrous, inert atmosphereTHF or DME, 0–25 °CTHF or DME, –78 °C → 25 °C
StereochemistryUnstabilised ylides: Z-alkene; stabilised: E-alkeneStrong E-selectivity (trans)Highly E-selective (anti-adduct, then anti elimination)
Rate / selectivityDriven by the strong P=O bond of Ph₃P=OAldehyde addition rate-limiting; water-soluble phosphate easily removedOne-pot; Smiles shift and elimination are fast after addition

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Wittig reaction?

Ph₃P=CH₂ (ylide, from Ph₃P⁺CH₃ Br⁻ + n-BuLi); acetaldehyde. Conditions: THF, 0 °C → 25 °C; anhydrous, inert atmosphere.

Which bonds are formed and which are broken?

Formed: C=C π; P=O (very strong, ~130 kcal/mol). Broken: C=O π; P–C.

What is the stereochemical outcome?

Unstabilised ylides: Z-alkene; stabilised: E-alkene

What controls the rate or the selectivity?

Driven by the strong P=O bond of Ph₃P=O

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