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Alkene synthesis from hydrazone

Shapiro reaction

How the Shapiro reaction works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: TsNHNH₂; 2 equiv n-BuLi; then H₂O. Conditions: THF or TMEDA, –78 °C → 25 °C. Bonds formed: C=C; N₂; Ts⁻; bonds broken: α C–H; N–H; C–N; N–S. Stereochemistry: Less substituted alkene (kinetic deprotonation). Rate and selectivity: Dianion formation fast; N₂ loss irreversible.

At a glance

ReagentsTsNHNH₂; 2 equiv n-BuLi; then H₂O
Solvent / conditionsTHF or TMEDA, –78 °C → 25 °C
Bonds formedC=C; N₂; Ts⁻
Bonds brokenα C–H; N–H; C–N; N–S
StereochemistryLess substituted alkene (kinetic deprotonation)
Rate / selectivityDianion formation fast; N₂ loss irreversible

Step 1: Tosylhydrazone, then dianion

+cat. H⁺−H₂O2 n-BuLi, THF−2 BuHONH₂NHTsNNHTsNNHTsNNTs1 · TOSYLHYDRAZONE, THEN DIANIONtosylhydrazoneINTERMEDIATEdianionANIONTop: 2-butanone + TsNHNH₂ → tosylhydrazone. Bottom: first BuLi removes N–H, second removes the less hindered α C–H.

A ketone condenses with tosylhydrazine to form a tosylhydrazone, then two equivalents of strong base deprotonate both the N–H and an alpha C–H.

Step 2: Loss of Ts⁻ and N₂

−Ts⁻, −N₂++NNTsNNTs2 · LOSS OF TS⁻ AND N₂ene-hydrazide dianionANIONvinyl anion (vinyllithium)C₄H₇⁻ANIONdinitrogenN₂BYPRODUCTsulfinateLEAVING GROUPAnion lands on the former carbonyl carbon.

Loss of the sulfinate leaving group (Ts⁻) and N₂ gas occurs in a concerted fragmentation, forming a vinyl anion directly at the former carbonyl carbon.

Step 3: Protonation

++HOHOH3 · PROTONATIONvinyl anionC₄H₇⁻ANIONwaterH₂OACID1-buteneC₄H₈PRODUCThydroxideHO⁻BYPRODUCTGives the less substituted (terminal) alkene.

Aqueous workup protonates the vinyl anion, giving the less substituted alkene — a useful complement to Wittig or E2 methods when that regiochemistry is hard to access otherwise.

Abbreviations and terms

Ts
Tosyl. p-Toluenesulfonyl (p-CH₃C₆H₄SO₂–).
THF
Tetrahydrofuran. Cyclic ether solvent; its oxygen lone pairs solvate Li⁺/Mg²⁺ so organometallics stay dissolved and reactive.
n-BuLi
n-Butyllithium. Very strong base/nucleophile (pKa of butane ≈ 50); deprotonates alkynes and does lithium–halogen exchange.
TMEDA
N,N,N′,N′-Tetramethylethylenediamine. Chelates Li⁺ and breaks up RLi aggregates, making them more reactive.
H2
Hydrogen gas. Reductant for catalytic hydrogenation.
TS
Transition state. The highest-energy point on the pathway between two minima; it cannot be isolated.
E2
Bimolecular elimination. Concerted base removal of β-H and loss of the leaving group (anti-periplanar).

How it compares with related reactions

Shapiro reactionBamford-Stevens reactionHorner-Wadsworth-Emmons (HWE) reaction
ReagentsTsNHNH₂; 2 equiv n-BuLi; then H₂OTosylhydrazone, strong base (NaOMe, NaH, or NaOEt)Phosphonate ester (EtO)₂P(O)CH₂CO₂Et, NaH or NaOMe, aldehyde
ConditionsTHF or TMEDA, –78 °C → 25 °CAprotic solvent (diglyme, toluene), 100–200 °CTHF or DME, 0–25 °C
StereochemistryLess substituted alkene (kinetic deprotonation)Mixture of E/Z; thermodynamic (more substituted) alkene favouredStrong E-selectivity (trans)
Rate / selectivityDianion formation fast; N₂ loss irreversibleDiazo decomposition to carbene is rate-limitingAldehyde addition rate-limiting; water-soluble phosphate easily removed

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Shapiro reaction?

TsNHNH₂; 2 equiv n-BuLi; then H₂O. Conditions: THF or TMEDA, –78 °C → 25 °C.

Which bonds are formed and which are broken?

Formed: C=C; N₂; Ts⁻. Broken: α C–H; N–H; C–N; N–S.

What is the stereochemical outcome?

Less substituted alkene (kinetic deprotonation)

What controls the rate or the selectivity?

Dianion formation fast; N₂ loss irreversible

Study guides that help with this reaction

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