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Propargyl rearrangement — contrasting regiochemistry

Rupe rearrangement

How the Rupe rearrangement works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: Acid (H₂SO₄, HCO₂H, TsOH). Conditions: Heat, aqueous or neat acid. Bonds formed: C=C (enyne); C=O (after hydration); bonds broken: C–OH; α C–H; C≡C π. Stereochemistry: No new stereocenters. Rate and selectivity: Ionization/E1 loss of H⁺ is rate-limiting; hydration is slower.

At a glance

ReagentsAcid (H₂SO₄, HCO₂H, TsOH)
Solvent / conditionsHeat, aqueous or neat acid
Bonds formedC=C (enyne); C=O (after hydration)
Bonds brokenC–OH; α C–H; C≡C π
StereochemistryNo new stereocenters
Rate / selectivityIonization/E1 loss of H⁺ is rate-limiting; hydration is slower

Step 1: Ionization to the propargyl cation

H₃O⁺−H₂OOHOH₂1 · IONIZATION TO THE PROPARGYL CATION1-ethynylcyclohexanolC₈H₁₂OSUBSTRATEoxonium ionC₈H₁₃O⁺INTERMEDIATEpropargyl cationC₈H₁₁⁺CATIONSame cation as in Meyer–Schuster; an α-H on the ring is available.

A tertiary propargyl alcohol with an alpha hydrogen available ionizes under acid exactly as in the Meyer-Schuster, forming the same delocalized propargyl/allenyl cation.

Step 2: E1 loss of an α-proton

++HOH₂OH₃2 · E1 LOSS OF AN Α-PROTONpropargyl cationC₈H₁₁⁺CATIONwater (base)H₂OBASE1-ethynylcyclohexeneC₈H₁₀INTERMEDIATEhydroniumBYPRODUCTNo oxygen is retained: the conjugated enyne forms instead of the Meyer–Schuster enone.

But here, instead of water re-adding to the far carbon, loss of a proton from the carbon adjacent to the original carbinol carbon forms a conjugated enyne, without any net oxygen transposition.

Step 3: Markovnikov hydration, tautomerization

++−H⁺tautomerizeHOH₂OH₂OHO3 · MARKOVNIKOV HYDRATION, TAUTOMERIZATIONenyneC₈H₁₀SUBSTRATEhydroniumH₃O⁺ACIDvinyl cation (allylic)C₈H₁₁⁺CATIONvinyl cationCATIONwaterH₂ONUCLEOPHILEenolC₈H₁₂OINTERMEDIATE1-acetylcyclohexeneC₈H₁₂OPRODUCTThe carbonyl ends up on the original alkyne carbon next to the ring, not transposed as in Meyer–Schuster.

Acid-catalyzed Markovnikov hydration of that enyne's triple bond, followed by tautomerization, gives a different regiochemical outcome than Meyer-Schuster — an enone with the carbonyl positioned differently — showing how the same cationic intermediate can diverge to different products depending on which proton is lost versus which nucleophile re-adds.

Abbreviations and terms

H2
Hydrogen gas. Reductant for catalytic hydrogenation.
TsOH
p-Toluenesulfonic acid. Strong organic acid catalyst, soluble in organic solvents.
H2SO4
Sulfuric acid. Strong acid and dehydrating agent.
E1
Unimolecular elimination. Carbocation forms first, then a base removes a β-H.
Markovnikov
Markovnikov’s rule. In HX addition, H goes to the carbon with more H’s so the more stable cation forms.

How it compares with related reactions

Rupe rearrangementMeyer-Schuster rearrangementBamberger rearrangement
ReagentsAcid (H₂SO₄, HCO₂H, TsOH)Brønsted acid (H₂SO₄, TsOH) or Lewis acid; waterN-Phenylhydroxylamine, dilute H₂SO₄ (aq)
ConditionsHeat, aqueous or neat acidAqueous acid, heat (milder with Au or V catalysts)H₂O, 25–60 °C
StereochemistryNo new stereocenters(E)/(Z) mixture possible at the new alkeneNone; para-selective
Rate / selectivityIonization/E1 loss of H⁺ is rate-limiting; hydration is slowerRate-limiting 1,3-shift of OH via the stabilized cationLoss of water to give the nitrenium ion is rate-limiting

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Rupe rearrangement?

Acid (H₂SO₄, HCO₂H, TsOH). Conditions: Heat, aqueous or neat acid.

Which bonds are formed and which are broken?

Formed: C=C (enyne); C=O (after hydration). Broken: C–OH; α C–H; C≡C π.

What is the stereochemical outcome?

No new stereocenters

What controls the rate or the selectivity?

Ionization/E1 loss of H⁺ is rate-limiting; hydration is slower

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