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Rearrangement — N-oxide activation

Boekelheide rearrangement

How the Boekelheide rearrangement works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: 2-Methylpyridine N-oxide, Ac₂O (or TFAA); then aqueous base. Conditions: Ac₂O, reflux (TFAA works at 25 °C). Bonds formed: C–O (CH₂–OAc); N–C=C (aromatic ring restored); bonds broken: N–O; side-chain C–H. Stereochemistry: None (achiral product). Rate and selectivity: N-acylation fast; [3,3] shift rate-limiting.

At a glance

Reagents2-Methylpyridine N-oxide, Ac₂O (or TFAA); then aqueous base
Solvent / conditionsAc₂O, reflux (TFAA works at 25 °C)
Bonds formedC–O (CH₂–OAc); N–C=C (aromatic ring restored)
Bonds brokenN–O; side-chain C–H
StereochemistryNone (achiral product)
Rate / selectivityN-acylation fast; [3,3] shift rate-limiting

Step 1: Acylation turns N–O into a leaving group

++NOOOONOOOO1 · ACYLATION TURNS N–O INTO A LEAVING GROUP2-picoline N-oxideC₆H₇NONUCLEOPHILEacetic anhydrideC₄H₆O₃ELECTROPHILEN-acetoxypyridiniumC₈H₁₀NO₂⁺INTERMEDIATEacetateC₂H₃O₂⁻BASE

A heteroaromatic N-oxide (like a 2-alkylpyridine N-oxide) reacts with an activating anhydride (commonly acetic anhydride), converting the N-oxide oxygen into a good leaving group tethered right next to the ring nitrogen.

Step 2: Deprotonation, then [3,3] shift

++[3,3] shiftHNOOOONOOOOHNOOOON2 · DEPROTONATION, THEN [3,3] SHIFTN-acetoxypyridiniumC₈H₁₀NO₂⁺ACIDacetateC₂H₃O₂⁻BASEanhydrobaseC₈H₉NO₂INTERMEDIATEacetic acidC₂H₄O₂BYPRODUCTanhydrobaseC₈H₉NO₂INTERMEDIATE2-acetoxymethylpyridineC₈H₉NO₂INTERMEDIATESix-atom shift: CH₂=C–N–O–C=O gives AcO–CH₂; N–O breaks and the ring re-aromatises.

The benzylic-type C–H adjacent to the ring (on the alkyl substituent ortho to nitrogen) is deprotonated, and the resulting carbanion-like system undergoes an intramolecular [3,3]-sigmatropic-type shift, delivering the acyloxy group directly onto that benzylic carbon as the N–O bond breaks.

Step 3: Hydrolysis gives the alcohol

+H₂O+OONOHOHNOO3 · HYDROLYSIS GIVES THE ALCOHOL2-acetoxymethylpyridineC₈H₉NO₂ELECTROPHILEhydroxideHO⁻NUCLEOPHILE2-pyridylmethanolC₆H₇NOPRODUCTacetateC₂H₃O₂⁻BYPRODUCTNet: O moved from nitrogen to the side-chain carbon.

Hydrolysis of the resulting ester reveals a benzylic alcohol — net effect: an N-oxide oxygen has been transposed from nitrogen onto a side-chain carbon, the same conceptual outcome as an Overman rearrangement, just starting from a heteroaromatic N-oxide instead of an imidate.

Abbreviations and terms

OAc
Acetoxy. –OC(=O)CH₃, an acetate group.
Ac2O
Acetic anhydride. Acetylating agent.

How it compares with related reactions

Boekelheide rearrangementMeisenheimer rearrangementBamberger rearrangement
Reagents2-Methylpyridine N-oxide, Ac₂O (or TFAA); then aqueous baseAllylic tertiary amine N-oxideN-Phenylhydroxylamine, dilute H₂SO₄ (aq)
ConditionsAc₂O, reflux (TFAA works at 25 °C)Heat, 25–100 °C (neutral)H₂O, 25–60 °C
StereochemistryNone (achiral product)Suprafacial [2,3]; chirality transfer from N-oxide to carbonNone; para-selective
Rate / selectivityN-acylation fast; [3,3] shift rate-limitingConcerted, 5-membered envelope TS; unimolecularLoss of water to give the nitrenium ion is rate-limiting

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Boekelheide rearrangement?

2-Methylpyridine N-oxide, Ac₂O (or TFAA); then aqueous base. Conditions: Ac₂O, reflux (TFAA works at 25 °C).

Which bonds are formed and which are broken?

Formed: C–O (CH₂–OAc); N–C=C (aromatic ring restored). Broken: N–O; side-chain C–H.

What is the stereochemical outcome?

None (achiral product)

What controls the rate or the selectivity?

N-acylation fast; [3,3] shift rate-limiting

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