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Rearrangement — aryl ester to ketone

Fries rearrangement

How the Fries rearrangement works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: AlCl₃ (≥1 equiv; or BF₃, TfOH). Conditions: Low T (<60 °C) favors para; high T (>160 °C) favors ortho; neat or PhNO₂. Bonds formed: C–C (aryl–acyl); phenol O–H (after work-up); bonds broken: C(acyl)–O (aryl ester); aromatic C–H. Stereochemistry: Regiochemistry: para (kinetic, low T) vs ortho (chelated, high T). Rate and selectivity: Acylium formation and EAS both contribute; needs stoichiometric AlCl₃.

At a glance

ReagentsAlCl₃ (≥1 equiv; or BF₃, TfOH)
Solvent / conditionsLow T (<60 °C) favors para; high T (>160 °C) favors ortho; neat or PhNO₂
Bonds formedC–C (aryl–acyl); phenol O–H (after work-up)
Bonds brokenC(acyl)–O (aryl ester); aromatic C–H
StereochemistryRegiochemistry: para (kinetic, low T) vs ortho (chelated, high T)
Rate / selectivityAcylium formation and EAS both contribute; needs stoichiometric AlCl₃

Step 1: AlCl₃ complexes C=O, acylium forms

+ionization+OOAlClClClOAlClClClOOAlClClClOOClAlClClO1 · ALCL₃ COMPLEXES C=O, ACYLIUM FORMSphenyl acetateC₈H₈O₂SUBSTRATEaluminum chlorideAlCl₃CATALYSTLewis acid complexC₈H₈AlCl₃O₂INTERMEDIATELewis acid complexINTERMEDIATEacylium ionC₂H₃O⁺CATIONaryloxide–AlCl₃C₆H₅AlCl₃O⁻INTERMEDIATEThe weakened C–OAr bond breaks heterolytically to give the acylium electrophile.

AlCl₃ coordinates an aryl ester's carbonyl oxygen, weakening the O–aryl bond and eventually promoting its ionization to release a resonance-stabilized acylium ion — the same acylium electrophile used in Friedel-Crafts acylation, generated intramolecularly instead of from an acid chloride.

Step 2: Ring π attacks the acylium (para shown)

+OClAlClClOHClAlClClOO2 · RING Π ATTACKS THE ACYLIUM (PARA SHOWN)acylium ionC₂H₃O⁺ELECTROPHILEaryloxide–AlCl₃C₆H₅AlCl₃O⁻NUCLEOPHILEarenium ion (σ-complex)C₈H₈AlCl₃O₂INTERMEDIATEEAS: the O-donor directs ortho/para; the arenium cation is stabilized by the oxygen lone pair.

This acylium ion, still tethered nearby by the aluminum-phenoxide complex, is attacked by the ring's own π electrons in the same electrophilic aromatic substitution mechanism used throughout this library, reacting preferentially ortho or para to the original ester oxygen.

Step 3: Deprotonation, work-up

+−HClH₂O work-upClClAlClClOHOOOH3 · DEPROTONATION, WORK-UPchlorideCl⁻BASEarenium ionC₈H₈AlCl₃O₂INTERMEDIATE4-hydroxyacetophenoneC₈H₈O₂PRODUCTLosing H⁺ restores aromaticity; aqueous work-up frees the phenol from aluminum.

Loss of a proton restores aromaticity, giving a hydroxyaryl ketone — this converts an aryl ester directly into an ortho- or para-acylated phenol, using nothing but the ester's own acyl group as the incoming electrophile.

Abbreviations and terms

Lewis acid
Lewis acid. Electron-pair acceptor (AlCl₃, BF₃, TiCl₄…) that activates carbonyls and halides.
AlCl3
Aluminium chloride. Strong Lewis acid for Friedel–Crafts reactions.
BF3
Boron trifluoride. Lewis acid (usually as the Et₂O complex).
HCl
Hydrochloric acid / hydrogen chloride. Strong acid; chloride is the nucleophile in additions/substitutions.
EAS
Electrophilic aromatic substitution. An electrophile replaces H on an arene via a Wheland intermediate.
Wheland
Wheland intermediate (arenium ion). The cyclohexadienyl cation formed when an electrophile adds to a benzene ring.

How it compares with related reactions

Fries rearrangementBamberger rearrangementBeckmann rearrangement
ReagentsAlCl₃ (≥1 equiv; or BF₃, TfOH)N-Phenylhydroxylamine, dilute H₂SO₄ (aq)H₂SO₄, PCl₅, TsCl or PPA
ConditionsLow T (<60 °C) favors para; high T (>160 °C) favors ortho; neat or PhNO₂H₂O, 25–60 °CAcid, 100–130 °C (industrial: oleum)
StereochemistryRegiochemistry: para (kinetic, low T) vs ortho (chelated, high T)None; para-selectiveGroup anti to OH migrates, with retention
Rate / selectivityAcylium formation and EAS both contribute; needs stoichiometric AlCl₃Loss of water to give the nitrenium ion is rate-limitingMigration is rate-limiting; leaving-group ability of N–OX matters

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Fries rearrangement?

AlCl₃ (≥1 equiv; or BF₃, TfOH). Conditions: Low T (<60 °C) favors para; high T (>160 °C) favors ortho; neat or PhNO₂.

Which bonds are formed and which are broken?

Formed: C–C (aryl–acyl); phenol O–H (after work-up). Broken: C(acyl)–O (aryl ester); aromatic C–H.

What is the stereochemical outcome?

Regiochemistry: para (kinetic, low T) vs ortho (chelated, high T)

What controls the rate or the selectivity?

Acylium formation and EAS both contribute; needs stoichiometric AlCl₃

Study guides that help with this reaction

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