Nitrogen-extrusion rearrangement family
Hofmann rearrangement: amide → amine
How the Hofmann rearrangement works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.
In short. A 3-step mechanism. Typical reagents: Br₂, NaOH (or NaOBr), H₂O. Conditions: 0 °C then 50–70 °C. Bonds formed: C–N (R–N); N=C=O; N–H; bonds broken: N–H; C–R (migrates); N–Br. Stereochemistry: Migrating group retains configuration. Rate and selectivity: Concerted 1,2-shift is rate-determining; amine has one carbon fewer.
At a glance
Step 1: N-bromination and deprotonation
Br₂/NaOH brominate the amide nitrogen; base then deprotonates the remaining N–H, forming an anionic N-bromoamide.
Step 2: Concerted 1,2-shift
Loss of bromide triggers a concerted 1,2-shift: the R group migrates from carbon directly to nitrogen as bromide leaves, forming an isocyanate — the same migration logic as Curtius and Beckmann.
Step 3: Hydrolysis and decarboxylation
Hydroxide adds to the isocyanate and the resulting carbamic acid loses CO₂ spontaneously, giving a primary amine with one fewer carbon than the starting amide.
Abbreviations and terms
- R
- R group. Any carbon substituent (alkyl, aryl…) whose identity does not matter for the mechanism.
- NaOH
- Sodium hydroxide. Strong aqueous base and nucleophile.
- H2
- Hydrogen gas. Reductant for catalytic hydrogenation.
- Hofmann
- Hofmann product/rule. Elimination giving the less substituted alkene (bulky base or leaving group).
How it compares with related reactions
| Hofmann rearrangement | Lossen rearrangement | Schmidt reaction | |
|---|---|---|---|
| Reagents | Br₂, NaOH (or NaOBr), H₂O | Hydroxamic acid, activator (Ac₂O, TsCl), base | HN₃ (or NaN₃), H₂SO₄ or polyphosphoric acid |
| Conditions | 0 °C then 50–70 °C | Mild base, 25–100 °C, then H₂O | Strong acid, 25–80 °C; HN₃ is toxic and explosive |
| Stereochemistry | Migrating group retains configuration | Migrating group retains configuration | Migrating group retains configuration |
| Rate / selectivity | Concerted 1,2-shift is rate-determining; amine has one carbon fewer | Rate set by leaving-group ability of the O-acyl/O-sulfonyl group | N₂ loss and R-shift are concerted and irreversible |
Test yourself
Try to answer each question before opening it.
Which reagents and conditions are typical for the Hofmann rearrangement?
Br₂, NaOH (or NaOBr), H₂O. Conditions: 0 °C then 50–70 °C.
Which bonds are formed and which are broken?
Formed: C–N (R–N); N=C=O; N–H. Broken: N–H; C–R (migrates); N–Br.
What is the stereochemical outcome?
Migrating group retains configuration
What controls the rate or the selectivity?
Concerted 1,2-shift is rate-determining; amine has one carbon fewer
Study guides that help with this reaction
- Carbonyl chemistry: addition, acyl substitution and enolates
- Pericyclic reactions explained: cycloadditions, electrocyclisations and sigmatropic shifts
- Stereochemistry in mechanisms: inversion, retention, syn and anti