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Tandem Michael + aldol

Robinson annulation: building a ring in two steps

How the Robinson annulation works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: Ketone + methyl vinyl ketone (MVK); NaOEt or KOH. Conditions: EtOH, 25–80 °C; heat for dehydration. Bonds formed: C–C (Michael), C–C (aldol), C=C; bonds broken: α C–H (×2), C=C of MVK, C–OH. Stereochemistry: Quaternary stereocentre; often racemic (proline gives ee). Rate and selectivity: Michael first, then intramolecular aldol; E1cB dehydration last.

At a glance

ReagentsKetone + methyl vinyl ketone (MVK); NaOEt or KOH
Solvent / conditionsEtOH, 25–80 °C; heat for dehydration
Bonds formedC–C (Michael), C–C (aldol), C=C
Bonds brokenα C–H (×2), C=C of MVK, C–OH
StereochemistryQuaternary stereocentre; often racemic (proline gives ee)
Rate / selectivityMichael first, then intramolecular aldol; E1cB dehydration last

Step 1: Michael addition

+OOδ⁺OO1 · MICHAEL ADDITIONketone enolateC₇H₁₁O⁻NUCLEOPHILEmethyl vinyl ketoneC₄H₆OELECTROPHILE1,5-diketoneC₁₁H₁₈O₂INTERMEDIATEConjugate attack at the β-carbon; the new enolate is protonated.

An enolate performs a Michael addition onto an enone, forming a new C–C bond and a 1,5-diketone — the same conjugate addition covered earlier, now setting up ring formation.

Step 2: Intramolecular aldol

HO⁻−H₂Oring closurethen H₂OOOOOOOH2 · INTRAMOLECULAR ALDOL1,5-diketoneC₁₁H₁₈O₂INTERMEDIATEenolate (methyl side)C₁₁H₁₇O₂⁻ENOLATEβ-hydroxy ketone (aldol)C₁₁H₁₈O₂INTERMEDIATEThe methyl enolate attacks the ring C=O, closing a six-membered ring.

Under the same basic conditions, an intramolecular aldol addition then connects the two ends of that diketone chain, closing a new six-membered ring.

Step 3: Dehydration to the enone

HO⁻, heatE1cB+OOHOOH₂3 · DEHYDRATION TO THE ENONEβ-hydroxy ketoneC₁₁H₁₈O₂INTERMEDIATEbicyclic enone (octalone)C₁₁H₁₆OPRODUCTwaterH₂OBYPRODUCTLoss of H₂O gives the conjugated cyclohexenone; ring built from two C–C bonds.

Dehydration (E1cb, as in the aldol condensation) gives a conjugated cyclohexenone — the two mechanisms you already know, chained together to build rings.

Abbreviations and terms

EtOH
Ethanol. Polar protic solvent.
NaOEt
Sodium ethoxide. Alkoxide base matched to ethyl esters (avoids transesterification).
KOH
Potassium hydroxide. Strong aqueous/alcoholic base.
H2
Hydrogen gas. Reductant for catalytic hydrogenation.
E1cB
Elimination, unimolecular conjugate base. Deprotonation first to a carbanion, then loss of the leaving group.
ee
Enantiomeric excess. How much more of one enantiomer than the other is present.

How it compares with related reactions

Robinson annulationBaylis-Hillman reactionClaisen-Schmidt condensation
ReagentsKetone + methyl vinyl ketone (MVK); NaOEt or KOHActivated alkene (methyl acrylate), aldehyde, DABCO (10–100 mol %)Methyl ketone (ArCOCH₃), ArCHO (no α-H), NaOH or KOH
ConditionsEtOH, 25–80 °C; heat for dehydrationNeat or MeOH/CH₃CN, 25 °C, days (slow)EtOH/H₂O, 0–25 °C
StereochemistryQuaternary stereocentre; often racemic (proline gives ee)Racemic unless chiral amine/Brønsted acid usedE-chalcone (thermodynamic)
Rate / selectivityMichael first, then intramolecular aldol; E1cB dehydration lastProton transfer/elimination is rate-limiting; accelerated by protic additivesAldol addition reversible; E1cB dehydration drives it forward

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Robinson annulation?

Ketone + methyl vinyl ketone (MVK); NaOEt or KOH. Conditions: EtOH, 25–80 °C; heat for dehydration.

Which bonds are formed and which are broken?

Formed: C–C (Michael), C–C (aldol), C=C. Broken: α C–H (×2), C=C of MVK, C–OH.

What is the stereochemical outcome?

Quaternary stereocentre; often racemic (proline gives ee)

What controls the rate or the selectivity?

Michael first, then intramolecular aldol; E1cB dehydration last

Study guides that help with this reaction

Related mechanisms

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