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Intramolecular Claisen condensation

Dieckmann condensation

How the Dieckmann condensation works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: NaOEt (≥1 equiv), diethyl adipate. Conditions: EtOH or toluene, reflux; then H₃O⁺ workup. Bonds formed: Ring C–C bond (Cα–C=O); bonds broken: α C–H; C–OEt. Stereochemistry: New stereocentre — racemic. Rate and selectivity: 5- and 6-membered rings best; driven by β-keto ester deprotonation.

At a glance

ReagentsNaOEt (≥1 equiv), diethyl adipate
Solvent / conditionsEtOH or toluene, reflux; then H₃O⁺ workup
Bonds formedRing C–C bond (Cα–C=O)
Bonds brokenα C–H; C–OEt
StereochemistryNew stereocentre — racemic
Rate / selectivity5- and 6-membered rings best; driven by β-keto ester deprotonation

Step 1: Enolate formation

+OHOOOO1 · ENOLATE FORMATIONethoxideC₂H₅O⁻BASEdiethyl adipateC₁₀H₁₈O₄SUBSTRATEα-carbonEtO⁻ matches the ester OEt, so transesterification is invisible.

An alkoxide base deprotonates the α-carbon of one ester group in a diester, forming an ester enolate. The base should match the ester's alkoxy group (ethoxide with ethyl esters) so that any attack on the ester carbonyl is invisible.

Step 2: Intramolecular attack closes the ring

EtOOOEtO2 · INTRAMOLECULAR ATTACK CLOSES THE RINGester enolateNUCLEOPHILEattack1,6-diester → 5-membered ringCα attacks the distal ester C=O (5-exo closure).

The enolate attacks the other ester carbonyl in the same molecule, closing a ring. Five- and six-membered rings form best (from 1,6- and 1,7-diesters), and the tetrahedral intermediate then expels alkoxide.

Step 3: Collapse, deprotonation, workup

−EtO⁻+H₃O⁺workupOOOOOOOOOOOOOO3 · COLLAPSE, DEPROTONATION, WORKUPtetrahedral intermediateC₁₀H₁₇O₄⁻INTERMEDIATEβ-keto esterC₈H₁₂O₃PRODUCTethoxideC₂H₅O⁻BASEstabilised enolateC₈H₁₁O₃⁻INTERMEDIATE2-(ethoxycarbonyl)cyclopentanoneC₈H₁₂O₃PRODUCTpKa ≈ 11: the driving forceDeprotonating the β-keto ester (needs a full equiv of base) pulls the equilibrium forward.

The product is a cyclic β-keto ester. The reaction is driven by deprotonating that product between its two carbonyls (pKa about 11) — the same thermodynamic sink as the ordinary Claisen condensation — so a full equivalent of base is needed, and acid workup then gives the neutral β-keto ester.

Abbreviations and terms

OEt
Ethoxy. –OCH₂CH₃.
EtOH
Ethanol. Polar protic solvent.
NaOEt
Sodium ethoxide. Alkoxide base matched to ethyl esters (avoids transesterification).
pKa
Acid-dissociation constant (–log). Lower pKa = stronger acid; used to judge which proton a base removes.

How it compares with related reactions

Dieckmann condensationClaisen condensation of ethyl acetateClaisen-Schmidt condensation
ReagentsNaOEt (≥1 equiv), diethyl adipateEthyl acetate (2 equiv), NaOEt (≥ 1 equiv); then H₃O⁺Methyl ketone (ArCOCH₃), ArCHO (no α-H), NaOH or KOH
ConditionsEtOH or toluene, reflux; then H₃O⁺ workupEtOH, reflux; same alkoxide as ester OR groupEtOH/H₂O, 0–25 °C
StereochemistryNew stereocentre — racemicNone (achiral product)E-chalcone (thermodynamic)
Rate / selectivity5- and 6-membered rings best; driven by β-keto ester deprotonationEquilibrium pulled forward by deprotonating the β-keto ester (pKa ≈ 11)Aldol addition reversible; E1cB dehydration drives it forward

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Dieckmann condensation?

NaOEt (≥1 equiv), diethyl adipate. Conditions: EtOH or toluene, reflux; then H₃O⁺ workup.

Which bonds are formed and which are broken?

Formed: Ring C–C bond (Cα–C=O). Broken: α C–H; C–OEt.

What is the stereochemical outcome?

New stereocentre — racemic

What controls the rate or the selectivity?

5- and 6-membered rings best; driven by β-keto ester deprotonation

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