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Organocatalysis — enamine activation

Proline-catalyzed aldol reaction

How the Proline-catalyzed aldol reaction works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: L-Proline (10–30 mol%), acetone (donor), aldehyde (acceptor). Conditions: DMSO or DMF, 25 °C. Bonds formed: C–C (aldol); bonds broken: C=O π (aldehyde). Stereochemistry: High ee; Zimmerman–Traxler-like TS with COOH H-bond. Rate and selectivity: C–C bond formation from enamine is rate-limiting.

At a glance

ReagentsL-Proline (10–30 mol%), acetone (donor), aldehyde (acceptor)
Solvent / conditionsDMSO or DMF, 25 °C
Bonds formedC–C (aldol)
Bonds brokenC=O π (aldehyde)
StereochemistryHigh ee; Zimmerman–Traxler-like TS with COOH H-bond
Rate / selectivityC–C bond formation from enamine is rate-limiting

Step 1: Proline + ketone → enamine

+−H₂Ovia iminiumOHONHOOHON1 · PROLINE + KETONE → ENAMINEL-prolineC₅H₉NO₂CATALYSTacetoneC₃H₆OELECTROPHILEenamineC₈H₁₃NO₂NUCLEOPHILE

Proline's secondary amine condenses with a ketone donor to form an enamine — the same Schiff-base-derived enamine chemistry used by the aldolase enzyme covered much earlier, just with a small, chiral organic molecule standing in for the enzyme's active-site lysine.

Step 2: COOH directs the aldehyde; face-selective attack

+OHONOPhδ⁻OHONOHPh2 · COOH DIRECTS THE ALDEHYDE; FACE-SELECTIVE ATTACKenamineC₈H₁₃NO₂NUCLEOPHILEbenzaldehydeELECTROPHILEiminium aldolateINTERMEDIATECOOH H-bondsand directs face

Proline's own pendant carboxylic acid hydrogen-bonds to and activates the incoming aldehyde electrophile while simultaneously directing which face of the enamine attacks it — a single small molecule performing both the nucleophile-activation and the stereocontrol roles that a whole enzyme active site usually provides.

Step 3: Hydrolysis releases the aldol

++OHONOHPhOH₂OOHPhOHONH3 · HYDROLYSIS RELEASES THE ALDOLiminiumELECTROPHILEwaterH₂ONUCLEOPHILEaldol product (enantioenriched)PRODUCTL-prolineC₅H₉NO₂CATALYSTWater adds to C=N⁺ and the carbinolamine collapses, freeing proline.

Hydrolysis releases the aldol product with high enantioselectivity and regenerates proline — this discovery, that a simple amino acid could replicate enzyme-like aldolase stereocontrol, helped launch the field of asymmetric organocatalysis.

Abbreviations and terms

L
Ligand. A Lewis-base group (often a phosphine) bound to a metal centre.
Ph
Phenyl. –C₆H₅.
DMF
N,N-Dimethylformamide. Polar aprotic solvent – dissolves ionic nucleophiles but does not H-bond to them, speeding SN2 and SNAr.
DMSO
Dimethyl sulfoxide. Polar aprotic solvent; also the oxidant in Swern/Kornblum-type reactions.
H2
Hydrogen gas. Reductant for catalytic hydrogenation.
TS
Transition state. The highest-energy point on the pathway between two minima; it cannot be isolated.
ee
Enantiomeric excess. How much more of one enantiomer than the other is present.

How it compares with related reactions

Proline-catalyzed aldol reactionMacMillan iminium organocatalysisCBS reduction (Corey-Bakshi-Shibata)
ReagentsL-Proline (10–30 mol%), acetone (donor), aldehyde (acceptor)Chiral imidazolidinone·HCl (5–20 mol%), enal, nucleophile or diene(S)- or (R)-Me-CBS oxazaborolidine (5–10 mol%), BH₃·THF or BH₃·SMe₂
ConditionsDMSO or DMF, 25 °CMeOH/H₂O or CH₂Cl₂, 25 °CTHF, –20 to 25 °C, anhydrous
StereochemistryHigh ee; Zimmerman–Traxler-like TS with COOH H-bondHigh ee: bulky group shields one iminium facePredictable absolute configuration: hydride to the face set by the chiral boron-N framework
Rate / selectivityC–C bond formation from enamine is rate-limitingNucleophilic addition to the iminium is rate-limitingHydride transfer is rate-limiting; catalyst turnover fast

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Proline-catalyzed aldol reaction?

L-Proline (10–30 mol%), acetone (donor), aldehyde (acceptor). Conditions: DMSO or DMF, 25 °C.

Which bonds are formed and which are broken?

Formed: C–C (aldol). Broken: C=O π (aldehyde).

What is the stereochemical outcome?

High ee; Zimmerman–Traxler-like TS with COOH H-bond

What controls the rate or the selectivity?

C–C bond formation from enamine is rate-limiting

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