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Inorganic — coordination chemistry

Associative ligand substitution at a square-planar Pt(II) complex

How the Associative ligand substitution at a square-planar Pt(II) complex works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: K₂[PtCl₄] + NH₃ (aq). Conditions: H₂O, 25 °C. Bonds formed: Pt–N dative bond; bonds broken: Pt–Cl. Stereochemistry: Trigonal-bipyramidal intermediate; retention of geometry. Rate and selectivity: Rate = k₁[Pt] + k₂[Pt][NH₃] (associative; entering-ligand dependent).

At a glance

ReagentsK₂[PtCl₄] + NH₃ (aq)
Solvent / conditionsH₂O, 25 °C
Bonds formedPt–N dative bond
Bonds brokenPt–Cl
StereochemistryTrigonal-bipyramidal intermediate; retention of geometry
Rate / selectivityRate = k₁[Pt] + k₂[Pt][NH₃] (associative; entering-ligand dependent)

Step 1: NH₃ attacks the 16 e⁻ metal

+ClPtClClCl2NH₃1 · NH₃ ATTACKS THE 16 E⁻ METALtetrachloroplatinate(II)Cl₄Pt²⁻ELECTROPHILEammoniaH₃NNUCLEOPHILElone pair → Pt16 e⁻, open siteabove/below planed⁸ square-planar Pt(II) has an open coordination site above and below.

[PtCl₄]²⁻ is a 16-electron, coordinatively unsaturated square-planar complex — there's room for one more ligand. NH₃'s lone pair attacks the electrophilic metal center from above or below the plane.

Step 2: Five-coordinate intermediate

ClPtClClClNH₃32 · FIVE-COORDINATE INTERMEDIATEtrigonal-bipyramidal intermediateCl₄H₃NPt²⁻INTERMEDIATEAssociative (A) mechanism: bond to the entering ligand forms before the old one breaks.

This forms a five-coordinate, trigonal-bipyramidal intermediate — the defining feature of an associative (A) mechanism, common for d⁸ square-planar metals like Pt(II), Pd(II), and Au(III).

Step 3: Chloride leaves

+ClPtClClNH₃2Cl3 · CHLORIDE LEAVES[PtCl₃(NH₃)]⁻Cl₃H₃NPt⁻PRODUCTchlorideCl⁻LEAVING GROUPSquare-planar geometry is restored; cis-platin synthesis continues from here.

A chloride ligand leaves from the opposite face, restoring four-coordination and giving the substituted complex [PtCl₃(NH₃)]⁻.

How it compares with related reactions

Associative ligand substitution at a square-planar Pt(II) complexDissociative ligand substitution at an octahedral complexCuAAC
ReagentsK₂[PtCl₄] + NH₃ (aq)[Co(NH₃)₅Cl]²⁺ + H₂O (entering ligand Y)Terminal alkyne, organic azide, Cu(I) (CuSO₄ + sodium ascorbate, or CuI), base/ligand (TBTA)
ConditionsH₂O, 25 °CAqueous solution, 25 °CtBuOH/H₂O or DMSO, 25 °C
StereochemistryTrigonal-bipyramidal intermediate; retention of geometryOften retention (square-pyramidal intermediate)1,4-regioisomer only (thermal gives 1,4 + 1,5 mixture)
Rate / selectivityRate = k₁[Pt] + k₂[Pt][NH₃] (associative; entering-ligand dependent)Rate = k[complex]; independent of [Y] (D / Id)10⁷–10⁸ × faster than uncatalysed Huisgen cycloaddition

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Associative ligand substitution at a square-planar Pt(II) complex?

K₂[PtCl₄] + NH₃ (aq). Conditions: H₂O, 25 °C.

Which bonds are formed and which are broken?

Formed: Pt–N dative bond. Broken: Pt–Cl.

What is the stereochemical outcome?

Trigonal-bipyramidal intermediate; retention of geometry

What controls the rate or the selectivity?

Rate = k₁[Pt] + k₂[Pt][NH₃] (associative; entering-ligand dependent)

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