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Tandem cationic cyclization/rearrangement

Prins-pinacol tandem reaction

How the Prins-pinacol tandem reaction works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: Homoallylic diol bearing a tertiary carbinol, CH₂O (or acetal), Lewis acid (SnCl₄, BF₃·OEt₂) or Brønsted acid. Conditions: CH₂Cl₂, –78 to 25 °C. Bonds formed: C–C (ring closure); C–C (shifted group); C=O (ketone); bonds broken: C=C π; C–CH₃ (migrating group); C–OH₂⁺. Stereochemistry: Chair-like cyclisation; migration with retention at the migrating carbon. Rate and selectivity: Cyclisation is rate-limiting; the shift is fast.

At a glance

ReagentsHomoallylic diol bearing a tertiary carbinol, CH₂O (or acetal), Lewis acid (SnCl₄, BF₃·OEt₂) or Brønsted acid
Solvent / conditionsCH₂Cl₂, –78 to 25 °C
Bonds formedC–C (ring closure); C–C (shifted group); C=O (ketone)
Bonds brokenC=C π; C–CH₃ (migrating group); C–OH₂⁺
StereochemistryChair-like cyclisation; migration with retention at the migrating carbon
Rate / selectivityCyclisation is rate-limiting; the shift is fast

Step 1: Aldehyde activation, oxocarbenium ion

+−H₂OOHOHOHOHO1 · ALDEHYDE ACTIVATION, OXOCARBENIUM IONallylic diolNUCLEOPHILEprotonated formaldehydeCH₃O⁺ELECTROPHILEoxocarbenium ionCATIONThe primary OH condenses with CH₂O; the tertiary carbinol is kept for the later shift.

An acid-activated aldehyde is attacked by a nearby homoallylic alcohol's alkene, forming a new carbocation through the same Prins cyclization mechanism covered earlier — except here, the alcohol carbon also bears an adjacent leaving group set up for what comes next.

Step 2: Alkene attacks the C=O⁺: ring closes

Prins cyclisationOHOOHO2 · ALKENE ATTACKS THE C=O⁺: RING CLOSESoxocarbenium ionCATIONtertiary cation next to carbinolCATIONAlkene attack gives the 6-membered ether and a cation beside the carbinol carbon.

Rather than simply being trapped by the original oxygen (as in the standalone Prins reaction), this cation instead triggers a 1,2-alkyl or hydride shift from the adjacent carbinol carbon — the identical migration logic as the pinacol rearrangement, occurring immediately after, and directly triggered by, the Prins cyclization step.

Step 3: Pinacol-type shift, then proton loss

1,2-CH₃ shift−H⁺OOHOOHOO3 · PINACOL-TYPE SHIFT, THEN PROTON LOSScationCATIONprotonated ketoneCATION4,4-dimethyl-tetrahydropyran-3-oneC₇H₁₂O₂PRODUCTCH₃ migrates to the cation; the carbinol O lone pair forms C=O⁺ (the pinacol step); H⁺ loss gives the ketone.

Loss of a proton from the resulting oxocarbenium gives a ring-expanded or substituent-migrated cyclic ketone — chaining these two mechanisms together in one pot builds molecular complexity (a new ring plus a rearranged skeleton) far beyond what either the Prins or pinacol mechanism could deliver alone.

Abbreviations and terms

DCM
Dichloromethane. Common non-polar-ish solvent for reactions that need no nucleophilic or protic solvent.
Lewis acid
Lewis acid. Electron-pair acceptor (AlCl₃, BF₃, TiCl₄…) that activates carbonyls and halides.
BF3
Boron trifluoride. Lewis acid (usually as the Et₂O complex).

How it compares with related reactions

Prins-pinacol tandem reactionBamberger rearrangementBeckmann rearrangement
ReagentsHomoallylic diol bearing a tertiary carbinol, CH₂O (or acetal), Lewis acid (SnCl₄, BF₃·OEt₂) or Brønsted acidN-Phenylhydroxylamine, dilute H₂SO₄ (aq)H₂SO₄, PCl₅, TsCl or PPA
ConditionsCH₂Cl₂, –78 to 25 °CH₂O, 25–60 °CAcid, 100–130 °C (industrial: oleum)
StereochemistryChair-like cyclisation; migration with retention at the migrating carbonNone; para-selectiveGroup anti to OH migrates, with retention
Rate / selectivityCyclisation is rate-limiting; the shift is fastLoss of water to give the nitrenium ion is rate-limitingMigration is rate-limiting; leaving-group ability of N–OX matters

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Prins-pinacol tandem reaction?

Homoallylic diol bearing a tertiary carbinol, CH₂O (or acetal), Lewis acid (SnCl₄, BF₃·OEt₂) or Brønsted acid. Conditions: CH₂Cl₂, –78 to 25 °C.

Which bonds are formed and which are broken?

Formed: C–C (ring closure); C–C (shifted group); C=O (ketone). Broken: C=C π; C–CH₃ (migrating group); C–OH₂⁺.

What is the stereochemical outcome?

Chair-like cyclisation; migration with retention at the migrating carbon

What controls the rate or the selectivity?

Cyclisation is rate-limiting; the shift is fast

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