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Inorganic — coordination chemistry

Dissociative ligand substitution at an octahedral complex

How the Dissociative ligand substitution at an octahedral complex works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: [Co(NH₃)₅Cl]²⁺ + H₂O (entering ligand Y). Conditions: Aqueous solution, 25 °C. Bonds formed: Co–OH₂ bond; bonds broken: Co–Cl bond. Stereochemistry: Often retention (square-pyramidal intermediate). Rate and selectivity: Rate = k[complex]; independent of [Y] (D / Id).

At a glance

Reagents[Co(NH₃)₅Cl]²⁺ + H₂O (entering ligand Y)
Solvent / conditionsAqueous solution, 25 °C
Bonds formedCo–OH₂ bond
Bonds brokenCo–Cl bond
StereochemistryOften retention (square-pyramidal intermediate)
Rate / selectivityRate = k[complex]; independent of [Y] (D / Id)

Step 1: Six-coordinate: no free site

Co³⁺NH₃NH₃NH₃NH₃NH₃Cl1 · SIX-COORDINATE: NO FREE SITEoctahedral complex(18 e⁻, all sites filled)[Co(NH₃)₅Cl]²⁺SUBSTRATENothing can approach the metal, so the leaving group must go first.

Octahedral complexes already have all six coordination sites occupied — unlike square-planar Pt(II), there's no open site for an incoming ligand to attack first.

Step 2: Slow Co–Cl dissociation

slow−Cl⁻Co³⁺NH₃NH₃NH₃NH₃NH₃Cl‡Co³⁺NH₃NH₃NH₃NH₃NH₃2 · SLOW CO–CL DISSOCIATIONrate-determining step[Co(NH₃)₅Cl]²⁺TRANSITION STATEfive-coordinate intermediate(16 e⁻)[Co(NH₃)₅]³⁺INTERMEDIATEBond breaking is rate-determining; chloride leaves with its bonding pair.

A ligand leaves first, generating a five-coordinate intermediate. This step is rate-determining — the defining feature of a dissociative (D) mechanism.

Step 3: Fast capture by the entering ligand

+fastCo³⁺NH₃NH₃NH₃NH₃NH₃OH₂Co³⁺NH₃NH₃NH₃NH₃NH₃OH₂3 · FAST CAPTURE BY THE ENTERING LIGANDfive-coordinate intermediate[Co(NH₃)₅]³⁺INTERMEDIATEwater (entering ligand)H₂ONUCLEOPHILEaqua complex[Co(NH₃)₅(OH₂)]³⁺PRODUCTThe identity of the entering ligand barely changes the rate.

The new ligand then fills the vacant site rapidly. Because the rate depends only on how fast the leaving ligand departs, the incoming ligand's identity barely affects reaction rate.

Abbreviations and terms

H2
Hydrogen gas. Reductant for catalytic hydrogenation.
CO
Carbon monoxide (carbonyl ligand). σ-donor / strong π-acceptor ligand; also a C1 building block.

How it compares with related reactions

Dissociative ligand substitution at an octahedral complexAssociative ligand substitution at a square-planar Pt(II) complexCuAAC
Reagents[Co(NH₃)₅Cl]²⁺ + H₂O (entering ligand Y)K₂[PtCl₄] + NH₃ (aq)Terminal alkyne, organic azide, Cu(I) (CuSO₄ + sodium ascorbate, or CuI), base/ligand (TBTA)
ConditionsAqueous solution, 25 °CH₂O, 25 °CtBuOH/H₂O or DMSO, 25 °C
StereochemistryOften retention (square-pyramidal intermediate)Trigonal-bipyramidal intermediate; retention of geometry1,4-regioisomer only (thermal gives 1,4 + 1,5 mixture)
Rate / selectivityRate = k[complex]; independent of [Y] (D / Id)Rate = k₁[Pt] + k₂[Pt][NH₃] (associative; entering-ligand dependent)10⁷–10⁸ × faster than uncatalysed Huisgen cycloaddition

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Dissociative ligand substitution at an octahedral complex?

[Co(NH₃)₅Cl]²⁺ + H₂O (entering ligand Y). Conditions: Aqueous solution, 25 °C.

Which bonds are formed and which are broken?

Formed: Co–OH₂ bond. Broken: Co–Cl bond.

What is the stereochemical outcome?

Often retention (square-pyramidal intermediate)

What controls the rate or the selectivity?

Rate = k[complex]; independent of [Y] (D / Id)

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