Mechanism Lab Open the app

Boron — 1,2-migration/elimination

Zweifel olefination

How the Zweifel olefination works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

Open the interactive version

In short. A 3-step mechanism. Typical reagents: alkenyl–B(OR)₂, R′Li, I₂, NaOMe (or NaOH). Conditions: THF, −78 → 25 °C. Bonds formed: C–C (R′ to alkene carbon), new C=C; bonds broken: C–B, C–I. Stereochemistry: Net inversion of alkene geometry (E-boronate → Z-alkene). Rate and selectivity: Iodonium formation fast; anti-elimination fast with base.

At a glance

Reagentsalkenyl–B(OR)₂, R′Li, I₂, NaOMe (or NaOH)
Solvent / conditionsTHF, −78 → 25 °C
Bonds formedC–C (R′ to alkene carbon), new C=C
Bonds brokenC–B, C–I
StereochemistryNet inversion of alkene geometry (E-boronate → Z-alkene)
Rate / selectivityIodonium formation fast; anti-elimination fast with base

Step 1: Alkenyl boronate ate complex

++RBOOR'LiR'BOORLi1 · ALKENYL BORONATE ATE COMPLEXalkenylboronateELECTROPHILEorganolithiumNUCLEOPHILEboronate (ate) complexINTERMEDIATElithiumLi⁺BYPRODUCTAs in Matteson: the carbanion fills boron’s empty p orbital.

An alkenylboronate reacts with an organolithium reagent to form an ate complex, exactly as in the Matteson homologation's first step — boron's empty orbital accepting a new carbanion ligand.

Step 2: Iodonium, then 1,2-migration

++1,2-shift(anti to I)R'BOORIIR'BOORIIR'BOORIR'BOOIR2 · IODONIUM, THEN 1,2-MIGRATIONate complexINTERMEDIATEiodineI₂ELECTROPHILEiodonium ate complexINTERMEDIATEiodideI⁻BYPRODUCTiodonium ate complexINTERMEDIATEβ-iodoalkyl boronic esterINTERMEDIATER′ migrates to the α-carbon, anti to the departing iodonium C–I bond.

Electrophilic activation (commonly with I₂) of the alkene triggers the same kind of 1,2-migration seen in the Matteson reaction: an alkyl group migrates from boron to the adjacent, now-activated alkene carbon, displacing iodide as the migration terminus.

Step 3: Anti-elimination gives the alkene

+++R'BOOIROR'RIOBOO3 · ANTI-ELIMINATION GIVES THE ALKENEβ-iodoalkyl boronic esterINTERMEDIATEmethoxideCH₃O⁻BASEsubstituted alkenePRODUCTiodideI⁻BYPRODUCTtrimethyl borateC₃H₉BO₃BYPRODUCTAnti-periplanar B and I are lost together: new C=C, geometry inverted vs. start.

A base-mediated anti-periplanar elimination of boron and the remaining halide then forms the new alkene directly — the two-step migration-then-elimination sequence lets this reaction convert a vinylboronate into a fully substituted alkene with predictable geometry.

Abbreviations and terms

R
R group. Any carbon substituent (alkyl, aryl…) whose identity does not matter for the mechanism.
THF
Tetrahydrofuran. Cyclic ether solvent; its oxygen lone pairs solvate Li⁺/Mg²⁺ so organometallics stay dissolved and reactive.
NaOMe
Sodium methoxide. Alkoxide base matched to methyl esters.
NaOH
Sodium hydroxide. Strong aqueous base and nucleophile.

How it compares with related reactions

Zweifel olefinationMatteson homologationCBS reduction (Corey-Bakshi-Shibata)
Reagentsalkenyl–B(OR)₂, R′Li, I₂, NaOMe (or NaOH)R–B(OR′)₂, LiCHCl₂ (from CH₂Cl₂ + LDA or n-BuLi), then ZnCl₂ (cat.); R″MgX for next step(S)- or (R)-Me-CBS oxazaborolidine (5–10 mol%), BH₃·THF or BH₃·SMe₂
ConditionsTHF, −78 → 25 °CTHF, −100 → 25 °CTHF, –20 to 25 °C, anhydrous
StereochemistryNet inversion of alkene geometry (E-boronate → Z-alkene)R migrates with retention; the new CHCl carbon is set with inversion at Cl displacementPredictable absolute configuration: hydride to the face set by the chiral boron-N framework
Rate / selectivityIodonium formation fast; anti-elimination fast with baseZnCl₂ accelerates 1,2-shift; chiral diols (pinanediol) give >99:1 d.r.Hydride transfer is rate-limiting; catalyst turnover fast

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Zweifel olefination?

alkenyl–B(OR)₂, R′Li, I₂, NaOMe (or NaOH). Conditions: THF, −78 → 25 °C.

Which bonds are formed and which are broken?

Formed: C–C (R′ to alkene carbon), new C=C. Broken: C–B, C–I.

What is the stereochemical outcome?

Net inversion of alkene geometry (E-boronate → Z-alkene)

What controls the rate or the selectivity?

Iodonium formation fast; anti-elimination fast with base

Study guides that help with this reaction

Related mechanisms

Step through it interactively, then test yourself in Quiz