Mechanism Lab Open the app

Inorganic — asymmetric catalysis

Sharpless asymmetric epoxidation

How the Sharpless asymmetric epoxidation works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

Open the interactive version

In short. A 3-step mechanism. Typical reagents: Ti(OiPr)₄ (cat.), (+)- or (–)-DET/DIPT, tBuOOH. Conditions: CH₂Cl₂, –20 °C, 3 Å molecular sieves. Bonds formed: 2 C–O (epoxide); Ti–OtBu; bonds broken: O–O (peroxide); Ti–OiPr. Stereochemistry: Tartrate enantiomer dictates the epoxidised face; allylic OH required. Rate and selectivity: Ligand-accelerated; 80–95% yield, >90% ee typical.

At a glance

ReagentsTi(OiPr)₄ (cat.), (+)- or (–)-DET/DIPT, tBuOOH
Solvent / conditionsCH₂Cl₂, –20 °C, 3 Å molecular sieves
Bonds formed2 C–O (epoxide); Ti–OtBu
Bonds brokenO–O (peroxide); Ti–OiPr
StereochemistryTartrate enantiomer dictates the epoxidised face; allylic OH required
Rate / selectivityLigand-accelerated; 80–95% yield, >90% ee typical

Step 1: Ti binds alcohol and hydroperoxide

++– 2 iPrOHTiOiPrOiPrDETOHOHOTiDETOOO1 · TI BINDS ALCOHOL AND HYDROPEROXIDETi(tartrate) catalystCATALYSTallylic alcoholC₄H₈OSUBSTRATEtert-butyl hydroperoxideC₄H₁₀O₂OXIDANTloaded complexINTERMEDIATEBoth substrates exchange onto Ti in place of iPrO ligands; the tartrate fixes their relative geometry.

A titanium(IV) tartrate complex binds both the allylic alcohol substrate (through its oxygen) and tert-butyl hydroperoxide (through its oxygen) simultaneously, holding both reactive groups in a well-defined chiral pocket.

Step 2: Oxygen transfer to one alkene face

TiDETOOO‡2 · OXYGEN TRANSFER TO ONE ALKENE FACEoxygen-transfer TSTRANSITION STATETi-bound O is transferredtBuO⁻ leavesPeroxide O–O is cleaved as the C=C π bond attacks the Ti-bound oxygen from the face the chiral ligand exposes.

With both partners held rigidly by the same metal center, oxygen transfers directly from the peroxide to the alkene face that the chiral tartrate ligand makes accessible — the titanium's role is purely organizational, positioning the substrate for facially selective attack.

Step 3: One enantiomer of the epoxy alcohol

iPrOH or H₂O(ligand exchange)+TiDETOtBuOOOHOTiOiPrOiPrDET3 · ONE ENANTIOMER OF THE EPOXY ALCOHOLTi epoxy-alkoxideINTERMEDIATE2,3-epoxy alcoholsingle enantiomerC₄H₈O₂PRODUCTcatalyst regeneratedCATALYST(+)-tartrate and (–)-tartrate deliver oxygen to opposite faces, giving opposite enantiomers.

The alkene face reacted upon is fully predictable from which tartrate enantiomer (natural or unnatural) is used — this single method reliably gave synthetic chemists access to enantiopure epoxides for the first time and won its inventor a share of the 2001 Nobel Prize.

Abbreviations and terms

DCM
Dichloromethane. Common non-polar-ish solvent for reactions that need no nucleophilic or protic solvent.
TS
Transition state. The highest-energy point on the pathway between two minima; it cannot be isolated.
ee
Enantiomeric excess. How much more of one enantiomer than the other is present.

How it compares with related reactions

Sharpless asymmetric epoxidationAsymmetric phase-transfer catalysisCrabtree hydrogenation
ReagentsTi(OiPr)₄ (cat.), (+)- or (–)-DET/DIPT, tBuOOHChiral cinchona-derived Q*⁺Br⁻ (1–10 mol%), 50% aq. KOH, glycine imine tBu ester, BnBr[Ir(cod)(PCy₃)(py)]⁺ PF₆⁻, H₂ (1 atm)
ConditionsCH₂Cl₂, –20 °C, 3 Å molecular sievesToluene/CH₂Cl₂, 0 °C, vigorous stirringCH₂Cl₂, 25 °C
StereochemistryTartrate enantiomer dictates the epoxidised face; allylic OH requiredHigh ee: chiral ion pair shields one enolate faceFace selectivity set by the directing OH
Rate / selectivityLigand-accelerated; 80–95% yield, >90% ee typicalAlkylation of the ion pair is rate-limitingAlkene insertion/oxidative addition; works for tetrasubstituted alkenes

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Sharpless asymmetric epoxidation?

Ti(OiPr)₄ (cat.), (+)- or (–)-DET/DIPT, tBuOOH. Conditions: CH₂Cl₂, –20 °C, 3 Å molecular sieves.

Which bonds are formed and which are broken?

Formed: 2 C–O (epoxide); Ti–OtBu. Broken: O–O (peroxide); Ti–OiPr.

What is the stereochemical outcome?

Tartrate enantiomer dictates the epoxidised face; allylic OH required

What controls the rate or the selectivity?

Ligand-accelerated; 80–95% yield, >90% ee typical

Study guides that help with this reaction

Related mechanisms

Step through it interactively, then test yourself in Quiz