Mechanism Lab Open the app

Rearrangement — epoxy alcohol isomerization

Payne rearrangement

How the Payne rearrangement works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

Open the interactive version

In short. A 3-step mechanism. Typical reagents: 2,3-Epoxy alcohol, aqueous NaOH or t-BuOK (catalytic to stoichiometric base). Conditions: H₂O/THF or t-BuOH, 0–25 °C. Bonds formed: new epoxide C–O; O–H (new alcohol); bonds broken: old epoxide C–O; O–H (deprotonated). Stereochemistry: Inversion at the attacked carbon (SN2); chirality transferred. Rate and selectivity: Reversible; position set by epoxide substitution; can be trapped by nucleophiles.

At a glance

Reagents2,3-Epoxy alcohol, aqueous NaOH or t-BuOK (catalytic to stoichiometric base)
Solvent / conditionsH₂O/THF or t-BuOH, 0–25 °C
Bonds formednew epoxide C–O; O–H (new alcohol)
Bonds brokenold epoxide C–O; O–H (deprotonated)
StereochemistryInversion at the attacked carbon (SN2); chirality transferred
Rate / selectivityReversible; position set by epoxide substitution; can be trapped by nucleophiles

Step 1: Deprotonation of the hydroxyl

++HOOOHOOOH₂1 · DEPROTONATION OF THE HYDROXYL2,3-epoxy alcoholC₄H₈O₂SUBSTRATEhydroxideHO⁻BASEepoxy alkoxideC₄H₇O₂⁻ANIONwaterBYPRODUCTThe alkoxide now sits one carbon from the strained ring.

Under basic conditions, a 2,3-epoxy alcohol's free hydroxyl is deprotonated, forming an alkoxide positioned right next to the strained epoxide ring.

Step 2: Intramolecular SN2 opens the epoxide

3-exo-tet SN2backside attackOOOO2 · INTRAMOLECULAR SN2 OPENS THE EPOXIDEepoxy alkoxideC₄H₇O₂⁻NUCLEOPHILEisomeric epoxy alkoxideC₄H₇O₂⁻ANIONattacked carboninvertsO1 attacks C3, displacing the old epoxide oxygen (now O⁻ on C4) and forming a new three-membered ring (O1–C2–C3).

That alkoxide oxygen attacks the adjacent epoxide carbon intramolecularly — a backside SN2 attack, exactly like any epoxide-opening nucleophile, just tethered in place — displacing the original epoxide oxygen as it opens.

Step 3: Protonation: the epoxide has moved

++baseOOHOHOHOOHOHOOHO3 · PROTONATION: THE EPOXIDE HAS MOVEDalkoxideC₄H₇O₂⁻ANIONwaterH₂OACID1,2-epoxy-3-olC₄H₈O₂PRODUCThydroxideBASE2,3-epoxy-1-olSUBSTRATE1,2-epoxy-3-olPRODUCTBottom: the process is reversible; the equilibrium position depends on epoxide substitution (more substituted epoxide usually favoured).

The result is a new epoxide, shifted over by one carbon, with the original epoxide oxygen now the free hydroxyl — this reversible isomerization lets chemists effectively 'walk' an epoxide down a carbon chain under mild basic conditions.

Abbreviations and terms

THF
Tetrahydrofuran. Cyclic ether solvent; its oxygen lone pairs solvate Li⁺/Mg²⁺ so organometallics stay dissolved and reactive.
KOtBu
Potassium tert-butoxide. Strong, bulky alkoxide base – favours elimination over substitution.
NaOH
Sodium hydroxide. Strong aqueous base and nucleophile.
H2
Hydrogen gas. Reductant for catalytic hydrogenation.
SN2
Bimolecular nucleophilic substitution. One concerted step with backside attack and inversion; rate = k[RX][Nu].

How it compares with related reactions

Payne rearrangementBamberger rearrangementBeckmann rearrangement
Reagents2,3-Epoxy alcohol, aqueous NaOH or t-BuOK (catalytic to stoichiometric base)N-Phenylhydroxylamine, dilute H₂SO₄ (aq)H₂SO₄, PCl₅, TsCl or PPA
ConditionsH₂O/THF or t-BuOH, 0–25 °CH₂O, 25–60 °CAcid, 100–130 °C (industrial: oleum)
StereochemistryInversion at the attacked carbon (SN2); chirality transferredNone; para-selectiveGroup anti to OH migrates, with retention
Rate / selectivityReversible; position set by epoxide substitution; can be trapped by nucleophilesLoss of water to give the nitrenium ion is rate-limitingMigration is rate-limiting; leaving-group ability of N–OX matters

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Payne rearrangement?

2,3-Epoxy alcohol, aqueous NaOH or t-BuOK (catalytic to stoichiometric base). Conditions: H₂O/THF or t-BuOH, 0–25 °C.

Which bonds are formed and which are broken?

Formed: new epoxide C–O; O–H (new alcohol). Broken: old epoxide C–O; O–H (deprotonated).

What is the stereochemical outcome?

Inversion at the attacked carbon (SN2); chirality transferred

What controls the rate or the selectivity?

Reversible; position set by epoxide substitution; can be trapped by nucleophiles

Study guides that help with this reaction

Related mechanisms

Step through it interactively, then test yourself in Quiz