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Nucleophilic substitution at phosphorus

In-line phosphoryl transfer (SN2 at phosphorus)

How the In-line phosphoryl transfer (SN2 at phosphorus) works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: Phosphate triester model, nucleophile (HO⁻, ROH). Conditions: Aqueous / enzymatic, pH 7. Bonds formed: P–Nu; bonds broken: P–OAr (leaving group). Stereochemistry: Inversion at P (in-line, apical entry and exit). Rate and selectivity: Better leaving group (lower pKa) and better nucleophile accelerate.

At a glance

ReagentsPhosphate triester model, nucleophile (HO⁻, ROH)
Solvent / conditionsAqueous / enzymatic, pH 7
Bonds formedP–Nu
Bonds brokenP–OAr (leaving group)
StereochemistryInversion at P (in-line, apical entry and exit)
Rate / selectivityBetter leaving group (lower pKa) and better nucleophile accelerate

Step 1: In-line attack opposite the leaving group

+OHPOOOOArOHPOOOOAr‡1 · IN-LINE ATTACK OPPOSITE THE LEAVING GROUPhydroxideHO⁻NUCLEOPHILEphosphate triesterELECTROPHILEin-line attack (TS)TRANSITION STATENucleophile enters 180° from the leaving group (apical).

A nucleophile attacks phosphorus directly opposite the leaving group — 'in-line' attack, geometrically identical in concept to backside attack in carbon SN2, just at a different central atom.

Step 2: Pentacoordinate phosphorane

+OHPOOOOArOHPOOOOAr2 · PENTACOORDINATE PHOSPHORANEhydroxideHO⁻NUCLEOPHILEphosphate triesterELECTROPHILEtrigonal-bipyramidal phosphoraneINTERMEDIATENu, LG apical;3 O equatorialP expands its valence: a real intermediate, not just a TS.

Because phosphorus can expand its coordination number, the nucleophile and leaving group are both fully bonded at the same time, forming a genuine pentacoordinate phosphorane intermediate — a real species, not just a transition state, unlike carbon's SN2.

Step 3: Leaving group departs: inversion

loss of ArO⁻+OHPOOOOArHOPOOOArO3 · LEAVING GROUP DEPARTS: INVERSIONphosphoraneINTERMEDIATEdimethyl hydrogen phosphate (P inverted)PRODUCTaryloxideLEAVING GROUPThe three equatorial groups flip like an umbrella: net inversion at P.

The leaving group departs from the opposite face, giving inversion of configuration at phosphorus — this exact mechanism governs phosphate ester chemistry throughout biology, from ATP hydrolysis to DNA backbone cleavage.

Abbreviations and terms

Ar
Aryl group. Any aromatic ring substituent such as phenyl.
Nu
Nucleophile. An electron-rich species that donates an electron pair to form a new bond.
LG
Leaving group. The group that departs with the bonding electrons (good ones are weak bases: I⁻, Br⁻, TsO⁻…).
TS
Transition state. The highest-energy point on the pathway between two minima; it cannot be isolated.
SN2
Bimolecular nucleophilic substitution. One concerted step with backside attack and inversion; rate = k[RX][Nu].
pKa
Acid-dissociation constant (–log). Lower pKa = stronger acid; used to judge which proton a base removes.
ATP
Adenosine triphosphate. The cell’s energy currency; transfers phosphate groups.
DNA
Deoxyribonucleic acid. The genetic polymer.

How it compares with related reactions

In-line phosphoryl transfer (SN2 at phosphorus)Acid-catalyzed amide hydrolysisAmide synthesis from an acid chloride and amine
ReagentsPhosphate triester model, nucleophile (HO⁻, ROH)Amide, H₃O⁺ (HCl or H₂SO₄), H₂OBenzoyl chloride, methylamine, aqueous NaOH
ConditionsAqueous / enzymatic, pH 76 M acid, reflux (hours)CH₂Cl₂ / H₂O (biphasic), 0–25 °C
StereochemistryInversion at P (in-line, apical entry and exit)No stereocentre created; α-stereocentres retainedNo stereocentre; planar amide
Rate / selectivityBetter leaving group (lower pKa) and better nucleophile accelerateWater attack / C–N cleavage rate-limiting; far slower than ester hydrolysisVery fast; base neutralises HCl so the amine is not lost as its salt

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the In-line phosphoryl transfer (SN2 at phosphorus)?

Phosphate triester model, nucleophile (HO⁻, ROH). Conditions: Aqueous / enzymatic, pH 7.

Which bonds are formed and which are broken?

Formed: P–Nu. Broken: P–OAr (leaving group).

What is the stereochemical outcome?

Inversion at P (in-line, apical entry and exit)

What controls the rate or the selectivity?

Better leaving group (lower pKa) and better nucleophile accelerate

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