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Nucleophilic acyl substitution — Schotten-Baumann

Amide synthesis from an acid chloride and amine

How the Amide synthesis from an acid chloride and amine works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: Benzoyl chloride, methylamine, aqueous NaOH. Conditions: CH₂Cl₂ / H₂O (biphasic), 0–25 °C. Bonds formed: C–N (amide); bonds broken: C–Cl; N–H. Stereochemistry: No stereocentre; planar amide. Rate and selectivity: Very fast; base neutralises HCl so the amine is not lost as its salt.

At a glance

ReagentsBenzoyl chloride, methylamine, aqueous NaOH
Solvent / conditionsCH₂Cl₂ / H₂O (biphasic), 0–25 °C
Bonds formedC–N (amide)
Bonds brokenC–Cl; N–H
StereochemistryNo stereocentre; planar amide
Rate / selectivityVery fast; base neutralises HCl so the amine is not lost as its salt

Step 1: Amine attacks the acyl carbon

+NaOH(aq) / CH₂Cl₂0 °CNH₂OClδ⁻OClNH₂1 · AMINE ATTACKS THE ACYL CARBONmethylamineNUCLEOPHILEbenzoyl chlorideC₇H₅ClOELECTROPHILEtetrahedral intermediateINTERMEDIATENitrogen lone pair adds to C=O; the π bond moves onto oxygen.

An amine's nitrogen lone pair attacks the acid chloride's electrophilic carbonyl carbon — the nitrogen analog of the acid-chloride-plus-alcohol ester synthesis covered just before this, and just as fast.

Step 2: Chloride leaves

collapse+OClNH₂ONH₂Cl2 · CHLORIDE LEAVEStetrahedral intermediateINTERMEDIATEprotonated amideINTERMEDIATEchlorideCl⁻LEAVING GROUPC=O re-forms as Cl⁻ is expelled.

The tetrahedral intermediate collapses, expelling chloride and reforming the C=O — the same addition-elimination mechanism used throughout nucleophilic acyl substitution chemistry.

Step 3: Base removes N–H⁺

+++ONHHOHONHOH₂Cl3 · BASE REMOVES N–H⁺protonated amideACIDhydroxide (aq. NaOH)HO⁻BASEN-methylbenzamideC₈H₉NOPRODUCTwaterH₂OBYPRODUCTchlorideBYPRODUCTNaOH takes the proton and traps the HCl, so all of the amine ends as amide.

Because the amide nitrogen ends up protonated (as an ammonium salt) after this step, a base — often aqueous NaOH, run biphasically in what's specifically called the Schotten-Baumann conditions — is included to deprotonate it and neutralize the HCl byproduct, driving the reaction to completion and preventing the amine from simply being consumed as its hydrochloride salt.

Abbreviations and terms

DCM
Dichloromethane. Common non-polar-ish solvent for reactions that need no nucleophilic or protic solvent.
NaOH
Sodium hydroxide. Strong aqueous base and nucleophile.
H2
Hydrogen gas. Reductant for catalytic hydrogenation.
HCl
Hydrochloric acid / hydrogen chloride. Strong acid; chloride is the nucleophile in additions/substitutions.

How it compares with related reactions

Amide synthesis from an acid chloride and amineAcid-catalyzed amide hydrolysisBase hydrolysis (saponification) of an ester
ReagentsBenzoyl chloride, methylamine, aqueous NaOHAmide, H₃O⁺ (HCl or H₂SO₄), H₂ONaOH (aq), methyl acetate
ConditionsCH₂Cl₂ / H₂O (biphasic), 0–25 °C6 M acid, reflux (hours)H₂O/MeOH, reflux
StereochemistryNo stereocentre; planar amideNo stereocentre created; α-stereocentres retainedRetention at the acyl carbon (planar); no stereo here
Rate / selectivityVery fast; base neutralises HCl so the amine is not lost as its saltWater attack / C–N cleavage rate-limiting; far slower than ester hydrolysisRate = k[ester][HO⁻]; irreversible because the acid is deprotonated

Test yourself

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Which reagents and conditions are typical for the Amide synthesis from an acid chloride and amine?

Benzoyl chloride, methylamine, aqueous NaOH. Conditions: CH₂Cl₂ / H₂O (biphasic), 0–25 °C.

Which bonds are formed and which are broken?

Formed: C–N (amide). Broken: C–Cl; N–H.

What is the stereochemical outcome?

No stereocentre; planar amide

What controls the rate or the selectivity?

Very fast; base neutralises HCl so the amine is not lost as its salt

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