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Nucleophilic addition

Hydride adds to acetaldehyde's carbonyl

How the Hydride adds to acetaldehyde's carbonyl works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: NaBH₄ or LiAlH₄ (H⁻ source); then H₃O⁺ workup. Conditions: EtOH (NaBH₄) or dry Et₂O/THF (LiAlH₄), 0–25 °C. Bonds formed: C–H σ; O–H (workup); bonds broken: C=O π. Stereochemistry: Planar C=O: attack from either face; new stereocentre if R groups differ. Rate and selectivity: Aldehydes > ketones > esters in reactivity.

At a glance

ReagentsNaBH₄ or LiAlH₄ (H⁻ source); then H₃O⁺ workup
Solvent / conditionsEtOH (NaBH₄) or dry Et₂O/THF (LiAlH₄), 0–25 °C
Bonds formedC–H σ; O–H (workup)
Bonds brokenC=O π
StereochemistryPlanar C=O: attack from either face; new stereocentre if R groups differ
Rate / selectivityAldehydes > ketones > esters in reactivity

Step 1: Polarised carbonyl, strong nucleophile

+HOδ⁺δ⁻1 · POLARISED CARBONYL, STRONG NUCLEOPHILEhydrideH⁻NUCLEOPHILEacetaldehydeC₂H₄OELECTROPHILEelectrophilic COxygen pulls electron density from the carbonyl carbon.

The carbonyl carbon is electrophilic — oxygen pulls electron density away from it. Hydride (H⁻, delivered by a reducing agent) is a strong nucleophile.

Step 2: Hydride adds, π pair moves to O

+HOδ⁻2 · HYDRIDE ADDS, Π PAIR MOVES TO OhydrideH⁻NUCLEOPHILEacetaldehydeC₂H₄OELECTROPHILEattackCarbon cannot hold five bonds, so the π electrons go to oxygen.

Hydride's electron pair attacks the carbonyl carbon. As the new C–H bond forms, the C=O π pair moves entirely onto oxygen, since carbon can't hold five bonds.

Step 3: Alkoxide, then protonation

H₃O⁺workupOOH3 · ALKOXIDE, THEN PROTONATIONethoxideC₂H₅O⁻INTERMEDIATEethanolC₂H₆OPRODUCTCore step of every carbonyl reduction and Grignard addition.

The result is an alkoxide, which picks up a proton on workup to give ethanol. This is the core step of every carbonyl reduction and Grignard addition.

Abbreviations and terms

R
R group. Any carbon substituent (alkyl, aryl…) whose identity does not matter for the mechanism.
THF
Tetrahydrofuran. Cyclic ether solvent; its oxygen lone pairs solvate Li⁺/Mg²⁺ so organometallics stay dissolved and reactive.
Et2O
Diethyl ether. Low-boiling ether solvent, classic for Grignard reagents.
EtOH
Ethanol. Polar protic solvent.
LiAlH4
Lithium aluminium hydride. Powerful hydride (H⁻) donor; reduces esters, acids, amides to alcohols/amines.
NaBH4
Sodium borohydride. Mild hydride donor; reduces aldehydes and ketones but not esters.

How it compares with related reactions

Hydride adds to acetaldehyde's carbonylAcid-catalyzed amide hydrolysisAcid-catalyzed hydration of an alkene
ReagentsNaBH₄ or LiAlH₄ (H⁻ source); then H₃O⁺ workupAmide, H₃O⁺ (HCl or H₂SO₄), H₂ODilute H₂SO₄ or H₃PO₄ (H₃O⁺), H₂O
ConditionsEtOH (NaBH₄) or dry Et₂O/THF (LiAlH₄), 0–25 °C6 M acid, reflux (hours)25–100 °C; heat and excess water favour the alcohol
StereochemistryPlanar C=O: attack from either face; new stereocentre if R groups differNo stereocentre created; α-stereocentres retainedPlanar carbocation: racemic; Markovnikov regiochemistry
Rate / selectivityAldehydes > ketones > esters in reactivityWater attack / C–N cleavage rate-limiting; far slower than ester hydrolysisProtonation of the alkene is rate-determining

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Hydride adds to acetaldehyde's carbonyl?

NaBH₄ or LiAlH₄ (H⁻ source); then H₃O⁺ workup. Conditions: EtOH (NaBH₄) or dry Et₂O/THF (LiAlH₄), 0–25 °C.

Which bonds are formed and which are broken?

Formed: C–H σ; O–H (workup). Broken: C=O π.

What is the stereochemical outcome?

Planar C=O: attack from either face; new stereocentre if R groups differ

What controls the rate or the selectivity?

Aldehydes > ketones > esters in reactivity

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