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Anti-Markovnikov hydration (concerted)

Hydroboration-oxidation of propene

How the Hydroboration-oxidation of propene works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: 1) BH₃·THF 2) H₂O₂, NaOH. Conditions: THF, 0–25 °C; then oxidative workup. Bonds formed: C–B then C–O; C–H; bonds broken: C=C π; B–H; C–B. Stereochemistry: Syn addition; retention at C–B oxidation. Rate and selectivity: Fast; B adds to the less hindered carbon.

At a glance

Reagents1) BH₃·THF 2) H₂O₂, NaOH
Solvent / conditionsTHF, 0–25 °C; then oxidative workup
Bonds formedC–B then C–O; C–H
Bonds brokenC=C π; B–H; C–B
StereochemistrySyn addition; retention at C–B oxidation
Rate / selectivityFast; B adds to the less hindered carbon

Step 1: BH₃ meets the alkene

+BHHHδ⁺1 · BH₃ MEETS THE ALKENEpropeneC₃H₆NUCLEOPHILEboraneBH₃ELECTROPHILEπ → empty p on Bempty p orbitalBoron is electron-deficient (6 electrons).

BH₃ approaches the alkene; the π electrons and the B–H bond interact in a four-centered, fully concerted transition state — no carbocation ever forms.

Step 2: Four-centred concerted transition state

BHHH‡2 · FOUR-CENTRED CONCERTED TRANSITION STATEfour-centred transition stateC₃H₉BTRANSITION STATEB → less hindered CH → more substituted CB and H add to the same face: syn addition, no carbocation.

Boron bonds to the less hindered carbon while hydrogen delivers to the more substituted one, all in one step — this explains hydroboration's anti-Markovnikov regiochemistry and syn stereochemistry.

Step 3: Oxidative workup

H₂O₂, NaOHH₂O+BH₂OHOHBOHOH3 · OXIDATIVE WORKUPpropylboraneC₃H₉BINTERMEDIATEpropan-1-olC₃H₈OPRODUCTboric acid / borateBH₃O₃BYPRODUCTC–B → C–OretentionHOO⁻ adds to B, then alkyl migrates B→O; hydrolysis frees the alcohol.

Oxidative workup (H₂O₂/NaOH) replaces the C–B bond with C–OH with retention of configuration, giving the anti-Markovnikov alcohol.

Abbreviations and terms

THF
Tetrahydrofuran. Cyclic ether solvent; its oxygen lone pairs solvate Li⁺/Mg²⁺ so organometallics stay dissolved and reactive.
NaOH
Sodium hydroxide. Strong aqueous base and nucleophile.
BH3
Borane. Electron-deficient Lewis acid that adds H–B across alkenes.
H2
Hydrogen gas. Reductant for catalytic hydrogenation.
H2O2
Hydrogen peroxide. Oxidant; its anion HOO⁻ is an excellent nucleophile.
Markovnikov
Markovnikov’s rule. In HX addition, H goes to the carbon with more H’s so the more stable cation forms.
anti-Markovnikov
Anti-Markovnikov. The opposite regiochemistry (radical HBr addition, hydroboration).

How it compares with related reactions

Hydroboration-oxidation of propeneAcetic acid transfers a proton to waterAcid-catalyzed amide hydrolysis
Reagents1) BH₃·THF 2) H₂O₂, NaOHAcetic acid (pKa 4.76) + waterAmide, H₃O⁺ (HCl or H₂SO₄), H₂O
ConditionsTHF, 0–25 °C; then oxidative workupAqueous solution, 25 °C6 M acid, reflux (hours)
StereochemistrySyn addition; retention at C–B oxidationNone (achiral species)No stereocentre created; α-stereocentres retained
Rate / selectivityFast; B adds to the less hindered carbonEquilibrium: Ka = 1.8 × 10⁻⁵, lies mostly leftWater attack / C–N cleavage rate-limiting; far slower than ester hydrolysis

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Hydroboration-oxidation of propene?

1) BH₃·THF 2) H₂O₂, NaOH. Conditions: THF, 0–25 °C; then oxidative workup.

Which bonds are formed and which are broken?

Formed: C–B then C–O; C–H. Broken: C=C π; B–H; C–B.

What is the stereochemical outcome?

Syn addition; retention at C–B oxidation

What controls the rate or the selectivity?

Fast; B adds to the less hindered carbon

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