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Al-catalyzed disproportionation

Tishchenko reaction

How the Tishchenko reaction works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: 2 RCHO, cat. Al(OR)₃ (e.g. Al(OEt)₃ or Al(OiPr)₃). Conditions: Neat or toluene, 0–25 °C. Bonds formed: Ester C–O and C=O; C–H (new alkoxide CH₂); bonds broken: Aldehyde C=O; hemiacetal C–H. Stereochemistry: None (acetaldehyde example). Rate and selectivity: 1,5-hydride shift in a six-membered Al-bound cycle is turnover-limiting.

At a glance

Reagents2 RCHO, cat. Al(OR)₃ (e.g. Al(OEt)₃ or Al(OiPr)₃)
Solvent / conditionsNeat or toluene, 0–25 °C
Bonds formedEster C–O and C=O; C–H (new alkoxide CH₂)
Bonds brokenAldehyde C=O; hemiacetal C–H
StereochemistryNone (acetaldehyde example)
Rate / selectivity1,5-hydride shift in a six-membered Al-bound cycle is turnover-limiting

Step 1: Alkoxide adds to a bound aldehyde

add. of OEtOAlOOOOOAlOO1 · ALKOXIDE ADDS TO A BOUND ALDEHYDEAl(OEt)₃·CH₃CHOC₈H₁₉AlO₄ELECTROPHILEAl-hemiacetalateC₈H₁₉AlO₄INTERMEDIATESame nucleophilic addition as the first step of MPV reduction.

An aluminum alkoxide catalyst attacks one aldehyde's carbonyl carbon, forming a tetrahedral aluminum hemiacetal-like intermediate — the same nucleophilic addition logic as MPV reduction's first step.

Step 2: Intramolecular hydride transfer

OHOAlOO2 · INTRAMOLECULAR HYDRIDE TRANSFERhemiacetalate + 2nd aldehydeC₈H₁₈AlO₄INTERMEDIATEhydride (1,5-shift)Six-membered cycle on Al; the hemiacetal C–H is the hydride donor.

This intermediate's alkoxide oxygen (or hydride, delivered intramolecularly) reduces a second aldehyde molecule bound to the same aluminum center — a self-contained, catalytic hydride-transfer disproportionation reminiscent of the Cannizzaro reaction, but requiring only catalytic aluminum rather than stoichiometric hydroxide.

Step 3: Ester released, catalyst regenerated

+OOAlOOO3 · ESTER RELEASED, CATALYST REGENERATEDethyl acetateC₄H₈O₂PRODUCTAl(OEt)₃CATALYSTOne aldehyde became the acyl part, the other the alkoxy part.

The result is one ester formed directly from two equivalents of the same aldehyde — one molecule is oxidized to the acyl portion, the other reduced to the alkoxy portion, both joined in a single catalytic cycle.

Abbreviations and terms

OEt
Ethoxy. –OCH₂CH₃.

How it compares with related reactions

Tishchenko reactionAcid-catalyzed hydration of an alkeneCannizzaro reaction of benzaldehyde
Reagents2 RCHO, cat. Al(OR)₃ (e.g. Al(OEt)₃ or Al(OiPr)₃)Dilute H₂SO₄ or H₃PO₄ (H₃O⁺), H₂OConc. NaOH or KOH (50 %)
ConditionsNeat or toluene, 0–25 °C25–100 °C; heat and excess water favour the alcoholAqueous/alcoholic, 25–80 °C; aldehyde lacks α-H
StereochemistryNone (acetaldehyde example)Planar carbocation: racemic; Markovnikov regiochemistryNot applicable (no new stereocentre)
Rate / selectivity1,5-hydride shift in a six-membered Al-bound cycle is turnover-limitingProtonation of the alkene is rate-determiningSecond order in aldehyde, first order in HO⁻ (rate-limiting hydride transfer)

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Tishchenko reaction?

2 RCHO, cat. Al(OR)₃ (e.g. Al(OEt)₃ or Al(OiPr)₃). Conditions: Neat or toluene, 0–25 °C.

Which bonds are formed and which are broken?

Formed: Ester C–O and C=O; C–H (new alkoxide CH₂). Broken: Aldehyde C=O; hemiacetal C–H.

What is the stereochemical outcome?

None (acetaldehyde example)

What controls the rate or the selectivity?

1,5-hydride shift in a six-membered Al-bound cycle is turnover-limiting

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