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Inorganic — organometallic

Reductive elimination: forming a C–C bond at a metal center

How the Reductive elimination works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: cis-(CH₃)(Ph)Pd(II)(PPh₃)₂. Conditions: Mild heat, THF or toluene; ligands must be cis. Bonds formed: C(sp³)–C(sp²) σ bond; bonds broken: Pd–CH₃ and Pd–Ph σ bonds. Stereochemistry: Retention at carbon; requires cis arrangement. Rate and selectivity: Faster with bulky ligands, electron-poor metals; the product-forming step of Suzuki/Negishi.

At a glance

Reagentscis-(CH₃)(Ph)Pd(II)(PPh₃)₂
Solvent / conditionsMild heat, THF or toluene; ligands must be cis
Bonds formedC(sp³)–C(sp²) σ bond
Bonds brokenPd–CH₃ and Pd–Ph σ bonds
StereochemistryRetention at carbon; requires cis arrangement
Rate / selectivityFaster with bulky ligands, electron-poor metals; the product-forming step of Suzuki/Negishi

Step 1: Two cis organic ligands on Pd(II)

CH₃Pd(II)PPh₃PPh₃Ph1 · TWO CIS ORGANIC LIGANDS ON PD(II)cis-methyl(phenyl)Pd(II)(PPh₃)₂SUBSTRATEcis: adjacentligandsCH₃ and Ph sit at 90° to each other.

Two organic groups — say, methyl and phenyl — sit cis to each other on a Pd(II) center, positioned close enough to interact directly.

Step 2: Pd–C bonds become the new C–C bond

CH₃Pd(II)PPh₃PPh₃Ph2 · PD–C BONDS BECOME THE NEW C–C BONDcis-methyl(phenyl)Pd(II)(PPh₃)₂TRANSITION STATEConcerted, three-centre: both M–C bonds break as C–C forms.

Electron density from the metal-carbon bonds flows to form a new C–C σ bond directly between the two organic fragments, while both M–C bonds break at once.

Step 3: Coupled product + Pd(0)

+PPh₃Pd(0)PPh₃3 · COUPLED PRODUCT + PD(0)tolueneC₇H₈PRODUCTPd(0)(PPh₃)₂CATALYSTOxidation state and coordination number each drop by 2; Pd(0) re-enters the cycle.

The metal's oxidation state and coordination number both drop by two (the reverse of oxidative addition), releasing the coupled organic product. This is the bond-forming step that finishes catalytic cycles like Suzuki and Negishi cross-coupling.

Abbreviations and terms

M
Metal. A generic metal centre.
Ph
Phenyl. –C₆H₅.
THF
Tetrahydrofuran. Cyclic ether solvent; its oxygen lone pairs solvate Li⁺/Mg²⁺ so organometallics stay dissolved and reactive.
PPh3
Triphenylphosphine. Nucleophilic phosphine; forms very strong P=O bonds, driving Wittig, Appel and Mitsunobu reactions.

How it compares with related reactions

Reductive eliminationCross metathesis between two different alkenesMigratory insertion
Reagentscis-(CH₃)(Ph)Pd(II)(PPh₃)₂Ru carbene (Grubbs II), two different alkenesLₙM–CH₃ (e.g. Mn(CO)₅CH₃) + CO
ConditionsMild heat, THF or toluene; ligands must be cisCH₂Cl₂, 25–40 °C; excess partner or ethylene removalCO atmosphere, 25–100 °C
StereochemistryRetention at carbon; requires cis arrangementUsually E-selective (thermodynamic)Alkyl migrates; stereochemistry at carbon retained
Rate / selectivityFaster with bulky ligands, electron-poor metals; the product-forming step of Suzuki/NegishiInitiation/phosphine-or-ether release often limits; [2+2] steps fastAlkyl must be cis to CO; ligand then fills the vacant site

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Reductive elimination?

cis-(CH₃)(Ph)Pd(II)(PPh₃)₂. Conditions: Mild heat, THF or toluene; ligands must be cis.

Which bonds are formed and which are broken?

Formed: C(sp³)–C(sp²) σ bond. Broken: Pd–CH₃ and Pd–Ph σ bonds.

What is the stereochemical outcome?

Retention at carbon; requires cis arrangement

What controls the rate or the selectivity?

Faster with bulky ligands, electron-poor metals; the product-forming step of Suzuki/Negishi

Study guides that help with this reaction

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