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Inorganic — organometallic

β-hydride elimination

How the β-hydride elimination works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: Metal alkyl with a β-H and a vacant cis site. Conditions: Often spontaneous at 25 °C; heat speeds it. Bonds formed: M–H; C=C π; bonds broken: β C–H; M–C. Stereochemistry: Syn elimination: M and β-H must be coplanar. Rate and selectivity: Blocked by 18 e⁻ saturation or no β-H (e.g. M–CH₃, M–CH₂Ph).

At a glance

ReagentsMetal alkyl with a β-H and a vacant cis site
Solvent / conditionsOften spontaneous at 25 °C; heat speeds it
Bonds formedM–H; C=C π
Bonds brokenβ C–H; M–C
StereochemistrySyn elimination: M and β-H must be coplanar
Rate / selectivityBlocked by 18 e⁻ saturation or no β-H (e.g. M–CH₃, M–CH₂Ph)

Step 1: β-H approaches the metal

LₙPdHH1 · Β-H APPROACHES THE METALmetal ethyl(agostic β C–H)C₂H₅PdSUBSTRATEβ-hydrogennear vacant siteA coplanar four-centre M–C–C–H arrangement is required.

A metal alkyl complex with an accessible β-hydrogen adopts a conformation where that hydrogen sits close to the empty orbital on the metal.

Step 2: Four-centre transition state

LₙPdHH‡2 · FOUR-CENTRE TRANSITION STATEsyn β-H elimination TSC₂H₅PdTRANSITION STATEThe M–C σ bond becomes the new C=C π bond.

The β C–H bond's electrons shift onto the metal, forming a new M–H bond while a π bond forms between the alpha and beta carbons — the reverse of migratory insertion of an alkene.

Step 3: Metal hydride with a bound alkene

HLₙPd3 · METAL HYDRIDE WITH A BOUND ALKENEhydrido alkene complexC₂H₅PdPRODUCTReverse of alkene insertion; releases the alkene and ends chain growth in Ziegler–Natta polymerisation.

The product is a metal hydride with a coordinated alkene — this step commonly limits the lifetime of metal alkyls and terminates chain-growth processes like Ziegler-Natta polymerization.

Abbreviations and terms

L
Ligand. A Lewis-base group (often a phosphine) bound to a metal centre.
M
Metal. A generic metal centre.
TS
Transition state. The highest-energy point on the pathway between two minima; it cannot be isolated.

How it compares with related reactions

β-hydride eliminationCross metathesis between two different alkenesMigratory insertion
ReagentsMetal alkyl with a β-H and a vacant cis siteRu carbene (Grubbs II), two different alkenesLₙM–CH₃ (e.g. Mn(CO)₅CH₃) + CO
ConditionsOften spontaneous at 25 °C; heat speeds itCH₂Cl₂, 25–40 °C; excess partner or ethylene removalCO atmosphere, 25–100 °C
StereochemistrySyn elimination: M and β-H must be coplanarUsually E-selective (thermodynamic)Alkyl migrates; stereochemistry at carbon retained
Rate / selectivityBlocked by 18 e⁻ saturation or no β-H (e.g. M–CH₃, M–CH₂Ph)Initiation/phosphine-or-ether release often limits; [2+2] steps fastAlkyl must be cis to CO; ligand then fills the vacant site

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the β-hydride elimination?

Metal alkyl with a β-H and a vacant cis site. Conditions: Often spontaneous at 25 °C; heat speeds it.

Which bonds are formed and which are broken?

Formed: M–H; C=C π. Broken: β C–H; M–C.

What is the stereochemical outcome?

Syn elimination: M and β-H must be coplanar

What controls the rate or the selectivity?

Blocked by 18 e⁻ saturation or no β-H (e.g. M–CH₃, M–CH₂Ph)

Study guides that help with this reaction

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