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Cu-catalyzed oxidative homocoupling

Glaser coupling

How the Glaser coupling works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: Terminal alkyne, CuCl (cat.), amine base (TMEDA/Et₃N), O₂ (air). Conditions: Acetone, MeOH or CH₂Cl₂, 25 °C (Hay variant: CuCl/TMEDA). Bonds formed: C(sp)–C(sp) σ (1,3-diyne); H₂O; bonds broken: terminal C–H (×2); Cu–C. Stereochemistry: Linear product; no stereocenters. Rate and selectivity: Copper acetylide formation fast; oxidative coupling step limits rate.

At a glance

ReagentsTerminal alkyne, CuCl (cat.), amine base (TMEDA/Et₃N), O₂ (air)
Solvent / conditionsAcetone, MeOH or CH₂Cl₂, 25 °C (Hay variant: CuCl/TMEDA)
Bonds formedC(sp)–C(sp) σ (1,3-diyne); H₂O
Bonds brokenterminal C–H (×2); Cu–C
StereochemistryLinear product; no stereocenters
Rate / selectivityCopper acetylide formation fast; oxidative coupling step limits rate

Step 1: Base and Cu(I) make the copper acetylide

+++NHCu(I)CuNH1 · BASE AND CU(I) MAKE THE COPPER ACETYLIDEtriethylamineC₆H₁₅NBASEphenylacetyleneC₈H₆ACIDcopper(I)CATALYSTcopper acetylideINTERMEDIATEtriethylammoniumBYPRODUCTCu(I) π-binds the alkyne and acidifies the C–H; the amine removes H⁺.

Cu(I), with O₂ or another mild oxidant present, deprotonates a terminal alkyne's acidic C–H, forming a copper acetylide — the same first step used in Sonogashira coupling and CuAAC.

Step 2: O₂ oxidizes copper; two acetylides meet

+oxidation+alkynyl transferCu(I)OOCu(II)Cu(II)Cu(I)Cu(III)2 · O₂ OXIDIZES COPPER; TWO ACETYLIDES MEETcopper(I) acetylideINTERMEDIATEoxygenO₂OXIDANTCu(II) acetylideINTERMEDIATECu(II) acetylideINTERMEDIATECu(I) acetylideNUCLEOPHILEbis(alkynyl)copper(III)INTERMEDIATEOxidation to Cu(II)/Cu(III) sets up coupling of two alkynyl groups (radical or two-electron path).

O₂ oxidizes this copper acetylide to a copper(II) or copper(III) acetylide, activating it toward radical or two-electron coupling with a second equivalent of copper acetylide.

Step 3: Reductive elimination gives the diyne

reductiveelimination+PhCu(III)PhCu(I)3 · REDUCTIVE ELIMINATION GIVES THE DIYNEbis(alkynyl)copper(III)INTERMEDIATE1,4-diphenylbuta-1,3-diyneC₁₆H₁₀PRODUCTcopper(I)CATALYSTThe 1,3-diyne is the symmetrical counterpart of the Cadiot–Chodkiewicz cross-coupling.

Reductive elimination-type coupling joins the two alkynyl fragments directly, forming a 1,3-diyne and regenerating Cu(I) — this is the symmetrical partner reaction to Cadiot-Chodkiewicz's unsymmetrical cross-coupling, using the identical copper acetylide chemistry.

Abbreviations and terms

Ph
Phenyl. –C₆H₅.
DCM
Dichloromethane. Common non-polar-ish solvent for reactions that need no nucleophilic or protic solvent.
MeOH
Methanol. Polar protic solvent (also a nucleophile in solvolysis).
Et3N
Triethylamine. Common tertiary-amine base that scavenges HCl.
TMEDA
N,N,N′,N′-Tetramethylethylenediamine. Chelates Li⁺ and breaks up RLi aggregates, making them more reactive.
CuAAC
Copper-catalysed azide–alkyne cycloaddition. The copper-catalysed “click” reaction giving 1,4-triazoles.

How it compares with related reactions

Glaser couplingBuchwald-Hartwig aminationBuchwald-Hartwig etherification
ReagentsTerminal alkyne, CuCl (cat.), amine base (TMEDA/Et₃N), O₂ (air)ArBr, R₂NH, Pd₂(dba)₃ / bulky phosphine (XPhos, BINAP), NaOtBuArBr, ROH, Pd₂(dba)₃ or Pd(OAc)₂ / bulky biaryl phosphine (RockPhos, tBuBrettPhos), Cs₂CO₃ or NaOtBu
ConditionsAcetone, MeOH or CH₂Cl₂, 25 °C (Hay variant: CuCl/TMEDA)Toluene or dioxane, 80–110 °CToluene or dioxane, 80–100 °C
StereochemistryLinear product; no stereocentersNo new stereocentre; retention of aryl geometryNo new stereocentre; aryl geometry retained
Rate / selectivityCopper acetylide formation fast; oxidative coupling step limits rateBulky, electron-rich ligand speeds oxidative addition and C–N reductive eliminationC–O reductive elimination is slow, so very bulky ligands are needed

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Glaser coupling?

Terminal alkyne, CuCl (cat.), amine base (TMEDA/Et₃N), O₂ (air). Conditions: Acetone, MeOH or CH₂Cl₂, 25 °C (Hay variant: CuCl/TMEDA).

Which bonds are formed and which are broken?

Formed: C(sp)–C(sp) σ (1,3-diyne); H₂O. Broken: terminal C–H (×2); Cu–C.

What is the stereochemical outcome?

Linear product; no stereocenters

What controls the rate or the selectivity?

Copper acetylide formation fast; oxidative coupling step limits rate

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