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Pd-catalyzed C–O coupling

Buchwald-Hartwig etherification

How the Buchwald-Hartwig etherification works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: ArBr, ROH, Pd₂(dba)₃ or Pd(OAc)₂ / bulky biaryl phosphine (RockPhos, tBuBrettPhos), Cs₂CO₃ or NaOtBu. Conditions: Toluene or dioxane, 80–100 °C. Bonds formed: Ar–O (C–O σ); bonds broken: Ar–Br; O–H. Stereochemistry: No new stereocentre; aryl geometry retained. Rate and selectivity: C–O reductive elimination is slow, so very bulky ligands are needed.

At a glance

ReagentsArBr, ROH, Pd₂(dba)₃ or Pd(OAc)₂ / bulky biaryl phosphine (RockPhos, tBuBrettPhos), Cs₂CO₃ or NaOtBu
Solvent / conditionsToluene or dioxane, 80–100 °C
Bonds formedAr–O (C–O σ)
Bonds brokenAr–Br; O–H
StereochemistryNo new stereocentre; aryl geometry retained
Rate / selectivityC–O reductive elimination is slow, so very bulky ligands are needed

Step 1: Oxidative addition

+oxidativeadditionPd(0)LBrPhPdBrL1 · OXIDATIVE ADDITIONPd(0) catalystCATALYSTbromobenzeneC₆H₅BrELECTROPHILEL–Pd(II)(Ph)BrINTERMEDIATESame first step as the amination: Pd inserts into the Ar–Br bond.

Pd(0), supported by a bulky phosphine ligand, oxidatively adds an aryl halide, forming Ar–Pd(II)–X — identical first step to Buchwald-Hartwig amination covered earlier.

Step 2: Alcohol binds, base removes O–H

++−tBuOH, −Br⁻PhPdBrLOHOPhPdOL2 · ALCOHOL BINDS, BASE REMOVES O–HL–Pd(II)(Ph)BrINTERMEDIATEmethanolNUCLEOPHILEtert-butoxideBASEPd alkoxide complexINTERMEDIATEThe alkoxide ligand takes the place that the amido group holds in the amination.

An alcohol coordinates to palladium and is deprotonated by base, forming an aryl-palladium-alkoxide complex — the oxygen analog of the amido complex formed in the amination version, occupying the same structural role that transmetalation fills in Suzuki-type couplings.

Step 3: Reductive elimination

reductiveelimination+PhPdOLOPd(0)L3 · REDUCTIVE ELIMINATIONcis-aryl Pd alkoxideINTERMEDIATEanisole (aryl alkyl ether)C₇H₈OPRODUCTPd(0) catalystCATALYSTC–O bond forms and Pd(0) re-enters the cycle.

Reductive elimination forges the new C–O bond and regenerates Pd(0) — swapping the nitrogen nucleophile for an oxygen one turns the identical three-step catalytic logic into a general method for building diaryl and alkyl-aryl ethers.

Abbreviations and terms

Ar
Aryl group. Any aromatic ring substituent such as phenyl.
X
Halogen / leaving group. Cl, Br or I (sometimes any leaving group).
L
Ligand. A Lewis-base group (often a phosphine) bound to a metal centre.
Ph
Phenyl. –C₆H₅.
OAc
Acetoxy. –OC(=O)CH₃, an acetate group.
Cs2CO3
Cesium carbonate. Mild, soluble inorganic base (the “cesium effect”).
Pd(OAc)2
Palladium(II) acetate. Pd(II) pre-catalyst, reduced in situ to Pd(0).
Pd2(dba)3
Tris(dibenzylideneacetone)dipalladium(0). Air-stable source of Pd(0).
dba
Dibenzylideneacetone. Weakly bound alkene ligand on Pd(0).

How it compares with related reactions

Buchwald-Hartwig etherificationBuchwald-Hartwig aminationCadiot-Chodkiewicz coupling
ReagentsArBr, ROH, Pd₂(dba)₃ or Pd(OAc)₂ / bulky biaryl phosphine (RockPhos, tBuBrettPhos), Cs₂CO₃ or NaOtBuArBr, R₂NH, Pd₂(dba)₃ / bulky phosphine (XPhos, BINAP), NaOtButerminal alkyne, 1-bromoalkyne, cat. CuCl, amine base (EtNH₂ or BuNH₂), NH₂OH·HCl
ConditionsToluene or dioxane, 80–100 °CToluene or dioxane, 80–110 °CMeOH or aq. amine, 0–25 °C, under N₂
StereochemistryNo new stereocentre; aryl geometry retainedNo new stereocentre; retention of aryl geometryNone (linear sp carbons)
Rate / selectivityC–O reductive elimination is slow, so very bulky ligands are neededBulky, electron-rich ligand speeds oxidative addition and C–N reductive eliminationCross-selective; NH₂OH keeps copper as Cu(I)

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Buchwald-Hartwig etherification?

ArBr, ROH, Pd₂(dba)₃ or Pd(OAc)₂ / bulky biaryl phosphine (RockPhos, tBuBrettPhos), Cs₂CO₃ or NaOtBu. Conditions: Toluene or dioxane, 80–100 °C.

Which bonds are formed and which are broken?

Formed: Ar–O (C–O σ). Broken: Ar–Br; O–H.

What is the stereochemical outcome?

No new stereocentre; aryl geometry retained

What controls the rate or the selectivity?

C–O reductive elimination is slow, so very bulky ligands are needed

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