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Ring contraction

Favorskii rearrangement

How the Favorskii rearrangement works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: α-Halo ketone with an α′-H; NaOH, NaOMe or amine. Conditions: MeOH / H₂O, 0–60 °C. Bonds formed: cyclopropanone; ring-contracted acid / ester; bonds broken: α′ C–H; C–Cl; ring C–C. Stereochemistry: Ring contraction by one carbon. Rate and selectivity: Enolate formation and cyclisation are fast; ring opening follows.

At a glance

Reagentsα-Halo ketone with an α′-H; NaOH, NaOMe or amine
Solvent / conditionsMeOH / H₂O, 0–60 °C
Bonds formedcyclopropanone; ring-contracted acid / ester
Bonds brokenα′ C–H; C–Cl; ring C–C
StereochemistryRing contraction by one carbon
Rate / selectivityEnolate formation and cyclisation are fast; ring opening follows

Step 1: Enolate closes a cyclopropanone

HO⁻−H₂OOClOCl1 · ENOLATE CLOSES A CYCLOPROPANONE2-chlorocyclohexanoneC₆H₉ClOSUBSTRATEenolate (α′-deprotonated)C₆H₈ClO⁻ENOLATEdisplaces ClIntramolecular SN2: the enolate carbon displaces chloride on the far α-carbon.

Base deprotonates the carbon opposite an α-halo ketone's halogen; the resulting enolate displaces the halide intramolecularly, closing a strained cyclopropanone ring.

Step 2: Hydroxide adds to the strained C=O

+OOH2 · HYDROXIDE ADDS TO THE STRAINED C=Obicyclic cyclopropanoneC₆H₈OELECTROPHILEhydroxideHO⁻NUCLEOPHILEattackRing strain makes the three-membered ketone very electrophilic.

A nucleophile (like hydroxide or an alkoxide) attacks the strained, highly electrophilic cyclopropanone carbonyl carbon.

Step 3: Ring opens: ring-contracted acid

H₂Oring openingthen protonationOOHOHO3 · RING OPENS: RING-CONTRACTED ACIDtetrahedral intermediateC₆H₉O₂⁻INTERMEDIATEcyclopentanecarboxylic acidC₆H₁₀O₂PRODUCTC–C cleavesThe C–C bond breaks to give the more stable carbanion; six-ring becomes five-ring.

The ring opens at the weaker of its two C–C bonds, relieving strain and giving a ring-contracted carboxylic acid or ester — one carbon smaller than the starting ketone's ring.

Abbreviations and terms

MeOH
Methanol. Polar protic solvent (also a nucleophile in solvolysis).
NaOMe
Sodium methoxide. Alkoxide base matched to methyl esters.
NaOH
Sodium hydroxide. Strong aqueous base and nucleophile.
SN2
Bimolecular nucleophilic substitution. One concerted step with backside attack and inversion; rate = k[RX][Nu].

How it compares with related reactions

Favorskii rearrangementAcetic acid transfers a proton to waterAcid-catalyzed amide hydrolysis
Reagentsα-Halo ketone with an α′-H; NaOH, NaOMe or amineAcetic acid (pKa 4.76) + waterAmide, H₃O⁺ (HCl or H₂SO₄), H₂O
ConditionsMeOH / H₂O, 0–60 °CAqueous solution, 25 °C6 M acid, reflux (hours)
StereochemistryRing contraction by one carbonNone (achiral species)No stereocentre created; α-stereocentres retained
Rate / selectivityEnolate formation and cyclisation are fast; ring opening followsEquilibrium: Ka = 1.8 × 10⁻⁵, lies mostly leftWater attack / C–N cleavage rate-limiting; far slower than ester hydrolysis

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Favorskii rearrangement?

α-Halo ketone with an α′-H; NaOH, NaOMe or amine. Conditions: MeOH / H₂O, 0–60 °C.

Which bonds are formed and which are broken?

Formed: cyclopropanone; ring-contracted acid / ester. Broken: α′ C–H; C–Cl; ring C–C.

What is the stereochemical outcome?

Ring contraction by one carbon

What controls the rate or the selectivity?

Enolate formation and cyclisation are fast; ring opening follows

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