Mechanism Lab Open the app

Reductive amination — formic acid variant

Eschweiler-Clark reaction

How the Eschweiler-Clark reaction works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

Open the interactive version

In short. A 3-step mechanism. Typical reagents: Amine, excess CH₂O (formalin), excess HCO₂H. Conditions: Aqueous, 80–100 °C. Bonds formed: N–CH₃ (×2); CO₂; H₂O; bonds broken: N–H; C=O (CH₂O); H–CO₂H. Stereochemistry: Chiral centres α to N are not racemised. Rate and selectivity: Hydride transfer to the iminium is rate-limiting; CO₂ loss makes it irreversible.

At a glance

ReagentsAmine, excess CH₂O (formalin), excess HCO₂H
Solvent / conditionsAqueous, 80–100 °C
Bonds formedN–CH₃ (×2); CO₂; H₂O
Bonds brokenN–H; C=O (CH₂O); H–CO₂H
StereochemistryChiral centres α to N are not racemised
Rate / selectivityHydride transfer to the iminium is rate-limiting; CO₂ loss makes it irreversible

Step 1: Amine + CH₂O → iminium ion

+−H₂O+RNH₂ORNH₂ORNHOH₂RNHOH₂1 · AMINE + CH₂O → IMINIUM IONprimary amineNUCLEOPHILEformaldehydeCH₂OELECTROPHILEzwitterionINTERMEDIATEprotonated carbinolamineINTERMEDIATEiminium ionINTERMEDIATEwaterH₂OBYPRODUCTSchiff-base chemistry: addition then acid-catalysed loss of water.

An amine condenses with formaldehyde to form an iminium ion — the same Schiff-base chemistry covered throughout this library.

Step 2: Formate delivers hydride, loses CO₂

++RNHHOORNHOO2 · FORMATE DELIVERS HYDRIDE, LOSES CO₂iminium ionELECTROPHILEformate (from HCO₂H)CHO₂⁻REDUCTANTN-methylaminePRODUCTcarbon dioxideCO₂BYPRODUCTDecarboxylative hydride transfer; irreversible because CO₂ escapes.

Formic acid, rather than a metal hydride, serves as the hydride donor: it transfers a hydride directly to the iminium carbon while itself losing CO₂ (a decarboxylative hydride transfer, related in spirit to the Cannizzaro's hydride shift).

Step 3: Repeat until tertiary

CH₂O, HCO₂H−CO₂, −H₂OCH₂O, HCO₂H−CO₂, −H₂ORNH₂RNHRN3 · REPEAT UNTIL TERTIARYprimary amineSUBSTRATEsecondary amineINTERMEDIATEN,N-dimethylaminePRODUCTTertiary amines cannot form an iminium ion, so quaternary ammonium salts are never produced.

The result is exhaustive N-methylation — because this cycle repeats with each remaining N–H, a primary amine is driven all the way to a tertiary N,N-dimethylamine using nothing but formaldehyde and formic acid as reagents.

Abbreviations and terms

R
R group. Any carbon substituent (alkyl, aryl…) whose identity does not matter for the mechanism.
H2
Hydrogen gas. Reductant for catalytic hydrogenation.

How it compares with related reactions

Eschweiler-Clark reactionLeuckart-Wallach reactionBorch reductive amination
ReagentsAmine, excess CH₂O (formalin), excess HCO₂HKetone, HCO₂NH₄ (or HCONH₂ / R₂NH + HCO₂H)Amine, ketone/aldehyde, NaBH₃CN
ConditionsAqueous, 80–100 °CNeat, 160–185 °CMeOH, pH 6–7 (AcOH), 25 °C
StereochemistryChiral centres α to N are not racemisedRacemic product at a new stereocentreNew stereocentre usually racemic (unless chiral amine/ketone)
Rate / selectivityHydride transfer to the iminium is rate-limiting; CO₂ loss makes it irreversibleHigh temperature needed; iminium formation reversible, hydride transfer irreversibleIminium formation is rate-limiting; iminium reduced much faster than ketone at this pH

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Eschweiler-Clark reaction?

Amine, excess CH₂O (formalin), excess HCO₂H. Conditions: Aqueous, 80–100 °C.

Which bonds are formed and which are broken?

Formed: N–CH₃ (×2); CO₂; H₂O. Broken: N–H; C=O (CH₂O); H–CO₂H.

What is the stereochemical outcome?

Chiral centres α to N are not racemised

What controls the rate or the selectivity?

Hydride transfer to the iminium is rate-limiting; CO₂ loss makes it irreversible

Study guides that help with this reaction

Related mechanisms

Step through it interactively, then test yourself in Quiz