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Reductive amination — mild hydride

Borch reductive amination

How the Borch reductive amination works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: Amine, ketone/aldehyde, NaBH₃CN. Conditions: MeOH, pH 6–7 (AcOH), 25 °C. Bonds formed: C–N; C–H; bonds broken: C=O; B–H. Stereochemistry: New stereocentre usually racemic (unless chiral amine/ketone). Rate and selectivity: Iminium formation is rate-limiting; iminium reduced much faster than ketone at this pH.

At a glance

ReagentsAmine, ketone/aldehyde, NaBH₃CN
Solvent / conditionsMeOH, pH 6–7 (AcOH), 25 °C
Bonds formedC–N; C–H
Bonds brokenC=O; B–H
StereochemistryNew stereocentre usually racemic (unless chiral amine/ketone)
Rate / selectivityIminium formation is rate-limiting; iminium reduced much faster than ketone at this pH

Step 1: Amine + ketone ⇌ iminium (pH 6–7)

+H⁺ (pH 6–7)−H₂ONH₂ONH1 · AMINE + KETONE ⇌ IMINIUM (PH 6–7)methylamineCH₅NNUCLEOPHILEcyclohexanoneC₆H₁₀OELECTROPHILEiminium ionC₇H₁₄N⁺INTERMEDIATEMildly acidic pH: enough H⁺ to activate C=O and form iminium, not enough to protonate all amine.

An amine and a ketone condense to form an iminium ion at a pH carefully controlled (mildly acidic) to favor iminium formation over unreacted starting material.

Step 2: Cyanoborohydride reduces the iminium

+NHHBHHNNH2 · CYANOBOROHYDRIDE REDUCES THE IMINIUMiminium ionC₇H₁₄N⁺ELECTROPHILENaBH₃CNREDUCTANTN-methylcyclohexylamineC₇H₁₅NPRODUCTThe electron-withdrawing CN makes B–H a weaker hydride donor than NaBH₄.

Sodium cyanoborohydride (NaBH₃CN), a much milder and more selective hydride source than NaBH₄, delivers hydride to the iminium carbon — its reduced reactivity means it reduces the iminium far faster than it reduces the starting ketone itself.

Step 3: Chemoselectivity: iminium ≫ ketone

NaBH₃CN, pH 6–7very slow✗NaBH₃CN, pH 6–7fastOOHNHNH3 · CHEMOSELECTIVITY: IMINIUM ≫ KETONEketoneSUBSTRATEalcohol (not formed)BYPRODUCTiminium ionELECTROPHILEaminePRODUCTOne-pot reductive amination without pre-forming the imine.

This selectivity for iminium over ketone is exactly what allows a one-pot mixture of amine, ketone, and hydride source to give a clean secondary or tertiary amine, without needing to pre-form and isolate the imine separately.

Abbreviations and terms

MeOH
Methanol. Polar protic solvent (also a nucleophile in solvolysis).
AcOH
Acetic acid. Weak acid and polar protic solvent.
NaBH4
Sodium borohydride. Mild hydride donor; reduces aldehydes and ketones but not esters.
NaBH3CN
Sodium cyanoborohydride. Mild reductant stable at pH 3–6; reduces iminium ions selectively (reductive amination).
H2
Hydrogen gas. Reductant for catalytic hydrogenation.

How it compares with related reactions

Borch reductive aminationEschweiler-Clark reactionLeuckart-Wallach reaction
ReagentsAmine, ketone/aldehyde, NaBH₃CNAmine, excess CH₂O (formalin), excess HCO₂HKetone, HCO₂NH₄ (or HCONH₂ / R₂NH + HCO₂H)
ConditionsMeOH, pH 6–7 (AcOH), 25 °CAqueous, 80–100 °CNeat, 160–185 °C
StereochemistryNew stereocentre usually racemic (unless chiral amine/ketone)Chiral centres α to N are not racemisedRacemic product at a new stereocentre
Rate / selectivityIminium formation is rate-limiting; iminium reduced much faster than ketone at this pHHydride transfer to the iminium is rate-limiting; CO₂ loss makes it irreversibleHigh temperature needed; iminium formation reversible, hydride transfer irreversible

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Borch reductive amination?

Amine, ketone/aldehyde, NaBH₃CN. Conditions: MeOH, pH 6–7 (AcOH), 25 °C.

Which bonds are formed and which are broken?

Formed: C–N; C–H. Broken: C=O; B–H.

What is the stereochemical outcome?

New stereocentre usually racemic (unless chiral amine/ketone)

What controls the rate or the selectivity?

Iminium formation is rate-limiting; iminium reduced much faster than ketone at this pH

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