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Organocuprate coupling

Corey-House synthesis

How the Corey-House synthesis works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: 2 R–Li, CuI; then R′–X (primary alkyl iodide, bromide or tosylate). Conditions: Et₂O or THF, –78 to 25 °C. Bonds formed: C–C (R–R′); bonds broken: C–X; one Cu–C. Stereochemistry: Inversion at a stereogenic sp³ C–X in many cases; best with 1° halides. Rate and selectivity: Soft, low-polarity C–Cu bond: little elimination or carbonyl attack vs RLi.

At a glance

Reagents2 R–Li, CuI; then R′–X (primary alkyl iodide, bromide or tosylate)
Solvent / conditionsEt₂O or THF, –78 to 25 °C
Bonds formedC–C (R–R′)
Bonds brokenC–X; one Cu–C
StereochemistryInversion at a stereogenic sp³ C–X in many cases; best with 1° halides
Rate / selectivitySoft, low-polarity C–Cu bond: little elimination or carbonyl attack vs RLi

Step 1: Gilman reagent forms

+Et₂O−LiI+LiCuICuLiI1 · GILMAN REAGENT FORMSmethyllithium (2 equiv)REAGENTcopper(I) iodideREAGENTlithium dimethylcuprate (Gilman)Me₂CuLiREAGENTlithium iodideBYPRODUCTThe C–Cu bond is much less polar than C–Li, so the cuprate is soft and selective.

Two equivalents of an alkyllithium react with copper(I) iodide to form a lithium dialkylcuprate (Gilman reagent), R₂CuLi. The carbon-copper bond is much less polar than the carbon-lithium bond, which makes the cuprate soft and far more selective than a Grignard reagent.

Step 2: Oxidative addition of R′–I

+oxidativeadditionCuICuI2 · OXIDATIVE ADDITION OF R′–IdimethylcuprateNUCLEOPHILE1-iodobutaneELECTROPHILECu(III) intermediateINTERMEDIATECu(I) → Cu(III): the alkyl group and iodide both end up on copper.

The cuprate transfers one of its R groups to an alkyl halide. The mechanism is usually described as oxidative addition of R′–X to copper to give a transient Cu(III) species, rather than a plain SN2. Primary alkyl halides work best, and the halide can be an iodide, bromide, or tosylate.

Step 3: Reductive elimination

reductiveelimination++CuICuLiI3 · REDUCTIVE ELIMINATIONCu(III) intermediateINTERMEDIATEpentane (R–R′)C₅H₁₂PRODUCTmethylcopperBYPRODUCTlithium iodideBYPRODUCTThe two alkyls couple selectively to Cu(I) with no homocoupled mixture.

Reductive elimination from the Cu(III) intermediate forms the new C–C bond, giving R–R′ and RCu. This is a clean way to couple two different alkyl groups, a job Wurtz coupling does poorly because it gives mixtures.

Abbreviations and terms

R
R group. Any carbon substituent (alkyl, aryl…) whose identity does not matter for the mechanism.
X
Halogen / leaving group. Cl, Br or I (sometimes any leaving group).
THF
Tetrahydrofuran. Cyclic ether solvent; its oxygen lone pairs solvate Li⁺/Mg²⁺ so organometallics stay dissolved and reactive.
Et2O
Diethyl ether. Low-boiling ether solvent, classic for Grignard reagents.
CuI
Copper(I) iodide. Co-catalyst for Sonogashira, Ullmann and click chemistry.
SN2
Bimolecular nucleophilic substitution. One concerted step with backside attack and inversion; rate = k[RX][Nu].

How it compares with related reactions

Corey-House synthesisJapp-Klingemann reactionMcMurry coupling
Reagents2 R–Li, CuI; then R′–X (primary alkyl iodide, bromide or tosylate)ArN₂⁺ Cl⁻, α-substituted β-ketoester, NaOAc or NaOHTiCl₃ or TiCl₄, Zn (or Zn–Cu, LiAlH₄)
ConditionsEt₂O or THF, –78 to 25 °CEtOH/H₂O, 0–5 °CTHF, reflux, inert atmosphere
StereochemistryInversion at a stereogenic sp³ C–X in many cases; best with 1° halidesHydrazone formed mainly as Z (H-bonded); E/Z mixtures possibleMixture of E/Z for unsymmetrical alkenes
Rate / selectivitySoft, low-polarity C–Cu bond: little elimination or carbonyl attack vs RLiAzo coupling is fast; deacylation by hydroxide is rate-limitingPinacol coupling at low T; deoxygenation needs heat

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Corey-House synthesis?

2 R–Li, CuI; then R′–X (primary alkyl iodide, bromide or tosylate). Conditions: Et₂O or THF, –78 to 25 °C.

Which bonds are formed and which are broken?

Formed: C–C (R–R′). Broken: C–X; one Cu–C.

What is the stereochemical outcome?

Inversion at a stereogenic sp³ C–X in many cases; best with 1° halides

What controls the rate or the selectivity?

Soft, low-polarity C–Cu bond: little elimination or carbonyl attack vs RLi

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