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Syn elimination — pericyclic

Chugaev elimination

How the Chugaev elimination works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: 1) NaH, CS₂, CH₃I 2) heat. Conditions: Neat or inert solvent, 100–250 °C. Bonds formed: C=C; C=O (COS part); S–H; bonds broken: β C–H; C–O. Stereochemistry: Syn elimination via cyclic 6-membered TS. Rate and selectivity: Intramolecular, first order; no base needed.

At a glance

Reagents1) NaH, CS₂, CH₃I 2) heat
Solvent / conditionsNeat or inert solvent, 100–250 °C
Bonds formedC=C; C=O (COS part); S–H
Bonds brokenβ C–H; C–O
StereochemistrySyn elimination via cyclic 6-membered TS
Rate / selectivityIntramolecular, first order; no base needed

Step 1: Alcohol → xanthate

NaH, CS₂then CH₃IOHOSS1 · ALCOHOL → XANTHATE2-butanolC₄H₁₀OSUBSTRATEmethyl xanthateC₆H₁₂OS₂INTERMEDIATESame xanthate ester used in the Barton–McCombie reaction.

An alcohol is converted to a xanthate ester (same intermediate used in Barton-McCombie), which is then simply heated.

Step 2: Six-membered cyclic transition state

SSOH‡2 · SIX-MEMBERED CYCLIC TRANSITION STATEcyclic six-membered TSC₆H₁₃OS₂TRANSITION STATESyn-periplanar H and O; S abstracts the β-H, π bond forms, C–O breaks.

A cyclic, six-membered transition state lets the C=S sulfur pull off a β-hydrogen while the C–O bond breaks and a new alkene π bond forms — all in one concerted, intramolecular step, needing no external base.

Step 3: Alkene + COS + CH₃SH

++SOSH3 · ALKENE + COS + CH₃SH2-buteneC₄H₈PRODUCTcarbonyl sulfideCOSBYPRODUCTmethanethiolCH₄SBYPRODUCTXanthate leaves as S=C(OH)SMe, which fragments to COS + MeSH.

Because the mechanism is syn-periplanar (unlike E2's anti requirement), Chugaev elimination gives predictable stereochemistry useful for kinetically controlled alkene synthesis.

Abbreviations and terms

NaH
Sodium hydride. Insoluble, irreversible base: removes H⁺ and bubbles off H₂.
TS
Transition state. The highest-energy point on the pathway between two minima; it cannot be isolated.
E2
Bimolecular elimination. Concerted base removal of β-H and loss of the leaving group (anti-periplanar).

How it compares with related reactions

Chugaev eliminationCope elimination1,3-dipolar cycloaddition
Reagents1) NaH, CS₂, CH₃I 2) heatH₂O₂ or mCPBA (oxidation); then heatNitrile oxide (from hydroximoyl chloride + Et₃N, or ArCH=NOH + NCS/base), alkene
ConditionsNeat or inert solvent, 100–250 °COxidation 0–25 °C; elimination 80–160 °C (milder in DMSO/THF)CH₂Cl₂ or toluene, 25–80 °C; no catalyst
StereochemistrySyn elimination via cyclic 6-membered TSSyn elimination via planar 5-membered TSSuprafacial, stereospecific (alkene geometry retained); 5-substituted regioisomer favored
Rate / selectivityIntramolecular, first order; no base neededIntramolecular, first order; faster in polar aprotic solventsConcerted, thermal; HOMO/LUMO of dipole and alkene both matter

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Chugaev elimination?

1) NaH, CS₂, CH₃I 2) heat. Conditions: Neat or inert solvent, 100–250 °C.

Which bonds are formed and which are broken?

Formed: C=C; C=O (COS part); S–H. Broken: β C–H; C–O.

What is the stereochemical outcome?

Syn elimination via cyclic 6-membered TS

What controls the rate or the selectivity?

Intramolecular, first order; no base needed

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