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Metabolism — urea cycle (final step)

Arginase: hydrolysis of arginine to urea

How the Arginase works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: L-Arginine, H₂O, arginase (Mn₂ site). Conditions: Liver mitochondria/cytosol, pH ~9 optimum, 37 °C. Bonds formed: C–O (urea C=O); N–H; bonds broken: C–N (guanidinium to Nδ); O–H. Stereochemistry: Planar guanidinium attacked from one face; no stereocentre created. Rate and selectivity: Very fast; metal-bridging hydroxide is the nucleophile.

At a glance

ReagentsL-Arginine, H₂O, arginase (Mn₂ site)
Solvent / conditionsLiver mitochondria/cytosol, pH ~9 optimum, 37 °C
Bonds formedC–O (urea C=O); N–H
Bonds brokenC–N (guanidinium to Nδ); O–H
StereochemistryPlanar guanidinium attacked from one face; no stereocentre created
Rate / selectivityVery fast; metal-bridging hydroxide is the nucleophile

Step 1: Mn²⁺-bridged hydroxide from water

++MnHOHMn22EnzOOMnOHMn22EnzOOH1 · MN²⁺-BRIDGED HYDROXIDE FROM WATERMn₂ site + waterCATALYSTAsp (base)BASEbridging hydroxideNUCLEOPHILEAsp–COOHBYPRODUCTAsp accepts H⁺ and the Mn₂ pair holds a ready hydroxide.

Arginase carries a binuclear Mn²⁺ center at its active site. A Mn²⁺-bridged hydroxide is generated from water, so the enzyme holds a ready-made hydroxide nucleophile next to the substrate's guanidinium group.

Step 2: Hydroxide attacks the guanidinium carbon

+MnOHMn22RNHNH₂NH₂2 · HYDROXIDE ATTACKS THE GUANIDINIUM CARBONbridging hydroxideNUCLEOPHILEarginine guanidiniumELECTROPHILEThe planar, electron-poor carbon bears three nitrogens.

The Mn²⁺-bound hydroxide attacks the guanidinium carbon (the planar, electron-poor carbon bonded to three nitrogens), forming a tetrahedral intermediate. The metal ions stabilize this intermediate and an active-site aspartate shuttles protons.

Step 3: Collapse releases urea and ornithine

Asp shuttles H⁺+RNH₂ONH₂NH₂NH₂NH₂ORNH₂3 · COLLAPSE RELEASES UREA AND ORNITHINEtetrahedral intermediateINTERMEDIATEureaCH₄N₂OPRODUCTornithine (δ-NH₂)PRODUCTstabilised by Mn²⁺Urea exits the body; ornithine returns to restart the cycle.

The tetrahedral intermediate collapses, expelling ornithine's δ-amine as the leaving group and releasing urea. This is the last step of the urea cycle: urea carries nitrogen waste out of the body, and ornithine returns to the mitochondria to restart the cycle.

Abbreviations and terms

R
R group. Any carbon substituent (alkyl, aryl…) whose identity does not matter for the mechanism.
L
Ligand. A Lewis-base group (often a phosphine) bound to a metal centre.
H2
Hydrogen gas. Reductant for catalytic hydrogenation.
Asp
Aspartate. Acidic amino acid.

How it compares with related reactions

ArginaseAconitaseCitrate synthase
ReagentsL-Arginine, H₂O, arginase (Mn₂ site)Citrate, [4Fe-4S] cluster (Fe₄ binds OH), enzyme base (Ser) and acidAcetyl-CoA, oxaloacetate, citrate synthase (His274, His320, Asp375)
ConditionsLiver mitochondria/cytosol, pH ~9 optimum, 37 °CMitochondrial matrix, pH ≈ 7.4, 37 °CMitochondrial matrix, pH ≈ 7.8, 37 °C
StereochemistryPlanar guanidinium attacked from one face; no stereocentre createdAnti elimination; the intermediate flips so water adds to the opposite carbonEnolate attacks the si face of oxaloacetate; pro-S citrate
Rate / selectivityVery fast; metal-bridging hydroxide is the nucleophileNear-equilibrium; citrate:isocitrate ≈ 90:10 at equilibriumHydrolysis of citryl-CoA (ΔG°′ ≈ −32 kJ/mol overall) makes the step irreversible

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Arginase?

L-Arginine, H₂O, arginase (Mn₂ site). Conditions: Liver mitochondria/cytosol, pH ~9 optimum, 37 °C.

Which bonds are formed and which are broken?

Formed: C–O (urea C=O); N–H. Broken: C–N (guanidinium to Nδ); O–H.

What is the stereochemical outcome?

Planar guanidinium attacked from one face; no stereocentre created

What controls the rate or the selectivity?

Very fast; metal-bridging hydroxide is the nucleophile

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