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Metabolism — citric acid cycle (step 2)

Aconitase: citrate to isocitrate isomerization

How the Aconitase works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: Citrate, [4Fe-4S] cluster (Fe₄ binds OH), enzyme base (Ser) and acid. Conditions: Mitochondrial matrix, pH ≈ 7.4, 37 °C. Bonds formed: C=C (cis-aconitate); then C–O at the other carbon; bonds broken: C–O (tertiary); C–H; then C=C π. Stereochemistry: Anti elimination; the intermediate flips so water adds to the opposite carbon. Rate and selectivity: Near-equilibrium; citrate:isocitrate ≈ 90:10 at equilibrium.

At a glance

ReagentsCitrate, [4Fe-4S] cluster (Fe₄ binds OH), enzyme base (Ser) and acid
Solvent / conditionsMitochondrial matrix, pH ≈ 7.4, 37 °C
Bonds formedC=C (cis-aconitate); then C–O at the other carbon
Bonds brokenC–O (tertiary); C–H; then C=C π
StereochemistryAnti elimination; the intermediate flips so water adds to the opposite carbon
Rate / selectivityNear-equilibrium; citrate:isocitrate ≈ 90:10 at equilibrium

Step 1: Fe–S polarizes the OH, E1cB-type loss of water

++BaseOHOHOHOOHOOHFe₄S₄1 · FE–S POLARIZES THE OH, E1CB-TYPE LOSS OF WATERSer (base)BASEcitrateC₇H₁₀O₇SUBSTRATEiron-sulfur clusterCATALYSTFe binds the OH

An iron-sulfur cluster in the enzyme's active site polarizes citrate's hydroxyl, helping it leave as water in an E1cb-type dehydration — the same elimination logic covered throughout this library's aldol condensation and Grob fragmentation entries, just enzyme-facilitated.

Step 2: cis-Aconitate stays bound

+OHOOOHOOHOH₂2 · CIS-ACONITATE STAYS BOUNDcis-aconitateC₆H₆O₆INTERMEDIATEwater (bound at Fe)BYPRODUCTThe intermediate is not released; it rotates 180° in the active site (the "flip").

This forms a bound intermediate, cis-aconitate, still held in the active site rather than released into solution.

Step 3: Water re-adds at the other carbon

+conjugate additionOH₂OHOOOHOOHOHOOOHOHOOH3 · WATER RE-ADDS AT THE OTHER CARBONwaterH₂ONUCLEOPHILEcis-aconitate (flipped)C₆H₆O₆ELECTROPHILEisocitrateC₆H₈O₇PRODUCTthen H⁺OH now on a secondary carbon (oxidizable); C3 gets the proton.

Water re-adds across the double bond at a different carbon than it left from — a formal dehydration/rehydration isomerization that relocates the hydroxyl group, converting the tertiary alcohol of citrate (which can't be directly oxidized) into the secondary alcohol of isocitrate (which can) — setting up the very next step's oxidation.

Abbreviations and terms

H2
Hydrogen gas. Reductant for catalytic hydrogenation.
E1cB
Elimination, unimolecular conjugate base. Deprotonation first to a carbanion, then loss of the leaving group.
RE
Reductive elimination. Two groups on a metal couple and leave, lowering the oxidation state by two.
Ser
Serine. Amino acid with a nucleophilic –OH.

How it compares with related reactions

AconitaseCitrate synthaseFumarase
ReagentsCitrate, [4Fe-4S] cluster (Fe₄ binds OH), enzyme base (Ser) and acidAcetyl-CoA, oxaloacetate, citrate synthase (His274, His320, Asp375)Fumarate, H₂O, active-site base (Ser/His) and acid
ConditionsMitochondrial matrix, pH ≈ 7.4, 37 °CMitochondrial matrix, pH ≈ 7.8, 37 °CMitochondrial matrix, pH ≈ 7.4
StereochemistryAnti elimination; the intermediate flips so water adds to the opposite carbonEnolate attacks the si face of oxaloacetate; pro-S citrateAnti addition on one face gives L-malate (S) only
Rate / selectivityNear-equilibrium; citrate:isocitrate ≈ 90:10 at equilibriumHydrolysis of citryl-CoA (ΔG°′ ≈ −32 kJ/mol overall) makes the step irreversibleNear diffusion-limited; reversible

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Aconitase?

Citrate, [4Fe-4S] cluster (Fe₄ binds OH), enzyme base (Ser) and acid. Conditions: Mitochondrial matrix, pH ≈ 7.4, 37 °C.

Which bonds are formed and which are broken?

Formed: C=C (cis-aconitate); then C–O at the other carbon. Broken: C–O (tertiary); C–H; then C=C π.

What is the stereochemical outcome?

Anti elimination; the intermediate flips so water adds to the opposite carbon

What controls the rate or the selectivity?

Near-equilibrium; citrate:isocitrate ≈ 90:10 at equilibrium

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