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Alcohol activation

Appel reaction: alcohol → alkyl halide

How the Appel reaction works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: PPh₃, CBr₄ (or CCl₄). Conditions: CH₂Cl₂, 0–25 °C. Bonds formed: C–Br; P=O; bonds broken: C–O; P–Br. Stereochemistry: Inversion at carbon (SN2). Rate and selectivity: Driven by strong P=O bond; works best on 1° and 2° alcohols.

At a glance

ReagentsPPh₃, CBr₄ (or CCl₄)
Solvent / conditionsCH₂Cl₂, 0–25 °C
Bonds formedC–Br; P=O
Bonds brokenC–O; P–Br
StereochemistryInversion at carbon (SN2)
Rate / selectivityDriven by strong P=O bond; works best on 1° and 2° alcohols

Step 1: O attacks activated phosphorus

+OHBrPPhPhPh1 · O ATTACKS ACTIVATED PHOSPHORUS2-butanolC₄H₁₀ONUCLEOPHILEbromophosphoniumELECTROPHILEPPh₃ + CBr₄ → Ph₃P⁺–Br CBr₃⁻; CBr₃⁻ then takes the O–H proton to give CHBr₃.

The alcohol's oxygen attacks electrophilic PPh₃ (already activated by CBr₄ or CCl₄), displacing a halide and forming an oxyphosphonium salt — a phosphorus-based leaving group far better than plain OH.

Step 2: Bromide displaces Ph₃P=O (SN2)

+BrOPPhPhPh2 · BROMIDE DISPLACES PH₃P=O (SN2)bromideBr⁻NUCLEOPHILEoxyphosphonium ionINTERMEDIATEbackside attack

The liberated halide ion then performs a backside SN2 attack on the carbon bearing that activated oxygen, exactly as it would on any good leaving group.

Step 3: Alkyl bromide + Ph₃P=O

++BrOPPhPhPhBrBrBr3 · ALKYL BROMIDE + PH₃P=O2-bromobutaneC₄H₉BrPRODUCTtriphenylphosphine oxideBYPRODUCTbromoformCHBr₃BYPRODUCTInversion of configuration; strong P=O bond drives the reaction.

Triphenylphosphine oxide (a very stable, thermodynamically favorable byproduct) is what drives this reaction forward, giving the alkyl halide with inversion of configuration.

Abbreviations and terms

Ph
Phenyl. –C₆H₅.
DCM
Dichloromethane. Common non-polar-ish solvent for reactions that need no nucleophilic or protic solvent.
PPh3
Triphenylphosphine. Nucleophilic phosphine; forms very strong P=O bonds, driving Wittig, Appel and Mitsunobu reactions.
SN2
Bimolecular nucleophilic substitution. One concerted step with backside attack and inversion; rate = k[RX][Nu].

How it compares with related reactions

Appel reactionMitsunobu reactionPolonovski reaction
ReagentsPPh₃, CBr₄ (or CCl₄)PPh₃, DEAD (or DIAD), acidic H–Nu (pKa < 13)Tertiary amine N-oxide, Ac₂O (or TFAA); then Nu⁻ (CN⁻, H⁻, enol)
ConditionsCH₂Cl₂, 0–25 °CTHF, 0 °C → 25 °CCH₂Cl₂, 0–25 °C
StereochemistryInversion at carbon (SN2)Clean inversion at the alcohol carbonIminium regiochemistry set by the more acidic/accessible α-H
Rate / selectivityDriven by strong P=O bond; works best on 1° and 2° alcoholsBetaine formation fast; SN2 step rate-limitingO-acylation fast; elimination is rate-limiting

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Appel reaction?

PPh₃, CBr₄ (or CCl₄). Conditions: CH₂Cl₂, 0–25 °C.

Which bonds are formed and which are broken?

Formed: C–Br; P=O. Broken: C–O; P–Br.

What is the stereochemical outcome?

Inversion at carbon (SN2)

What controls the rate or the selectivity?

Driven by strong P=O bond; works best on 1° and 2° alcohols

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