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Heterocycle synthesis — indole via nitro reduction

Reissert indole synthesis

How the Reissert indole synthesis works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: o-Nitrotoluene, (CO₂Et)₂, KOEt; then Zn/AcOH (or H₂, Pd/C). Conditions: EtOH/Et₂O, 25 °C; reduction 25–80 °C. Bonds formed: C–C (Claisen); N–H₂; C=N then C=C–N (indole ring); bonds broken: benzylic C–H; N–O (×2); C=O. Stereochemistry: None (aromatic). Rate and selectivity: Condensation limited by CH acidity (pKa ≈ 20).

At a glance

Reagentso-Nitrotoluene, (CO₂Et)₂, KOEt; then Zn/AcOH (or H₂, Pd/C)
Solvent / conditionsEtOH/Et₂O, 25 °C; reduction 25–80 °C
Bonds formedC–C (Claisen); N–H₂; C=N then C=C–N (indole ring)
Bonds brokenbenzylic C–H; N–O (×2); C=O
StereochemistryNone (aromatic)
Rate / selectivityCondensation limited by CH acidity (pKa ≈ 20)

Step 1: Benzylic carbanion, Claisen condensation

++−EtO⁻OHNOONOONOOOOOOOOONOO1 · BENZYLIC CARBANION, CLAISEN CONDENSATIONethoxideC₂H₅O⁻BASEo-nitrotolueneC₇H₇NO₂ACIDbenzylic carbanionC₇H₆NO₂⁻ANIONcarbanionNUCLEOPHILEdiethyl oxalateC₆H₁₀O₄ELECTROPHILEethyl o-nitrophenylpyruvateC₁₁H₁₁NO₅INTERMEDIATEThe oxalate ketone-like carbon (C16) is attacked; ethoxide then leaves from the tetrahedral intermediate.

Base deprotonates the acidic methyl group of an ortho-nitrotoluene, and the resulting benzylic carbanion attacks diethyl oxalate's electrophilic carbonyl carbon — an ordinary Claisen-condensation-type nucleophilic acyl substitution.

Step 2: Reduce NO₂ to NH₂

Zn, AcOH(or H₂, Pd/C)−2 H₂OOOONOOOOONH₂2 · REDUCE NO₂ TO NH₂nitro keto-esterC₁₁H₁₁NO₅SUBSTRATEamino keto-esterC₁₁H₁₃NO₃INTERMEDIATESix-electron reduction; the new aniline sits next to the ketone side chain.

The nitro group is then selectively reduced (commonly with Sn/HCl or catalytic hydrogenation) to an amine, generating a nucleophile positioned right next to the newly installed ketoester chain.

Step 3: Imine formation closes the ring

intramolecularaddition−H₂OtautomeriseNH₂OOOOHOONHOHOONHOONH3 · IMINE FORMATION CLOSES THE RINGamino keto-esterC₁₁H₁₃NO₃INTERMEDIATEcarbinolamineC₁₁H₁₃NO₃INTERMEDIATEcarbinolamineINTERMEDIATEethyl indole-2-carboxylateC₁₁H₁₁NO₂PRODUCTDehydration to the cyclic imine, then enamine tautomer = aromatic indole.

That amine condenses intramolecularly with the nearby ketone (ordinary Schiff-base imine formation) and tautomerizes, closing and aromatizing the five-membered ring to give an indole-2-carboxylate ester — this route builds the ring by installing the side chain before reducing the nitro group, the reverse order from most other indole syntheses in this library.

Abbreviations and terms

Et2O
Diethyl ether. Low-boiling ether solvent, classic for Grignard reagents.
EtOH
Ethanol. Polar protic solvent.
AcOH
Acetic acid. Weak acid and polar protic solvent.
Pd/C
Palladium on carbon. Heterogeneous hydrogenation catalyst.
H2
Hydrogen gas. Reductant for catalytic hydrogenation.
HCl
Hydrochloric acid / hydrogen chloride. Strong acid; chloride is the nucleophile in additions/substitutions.
pKa
Acid-dissociation constant (–log). Lower pKa = stronger acid; used to judge which proton a base removes.

How it compares with related reactions

Reissert indole synthesisBischler indole synthesisLeimgruber-Batcho indole synthesis
Reagentso-Nitrotoluene, (CO₂Et)₂, KOEt; then Zn/AcOH (or H₂, Pd/C)Aniline (excess), α-haloketone (PhCOCH₂Br)DMF-DMA (Me₂NCH(OMe)₂), pyrrolidine; then H₂, Pd/C or Raney Ni
ConditionsEtOH/Et₂O, 25 °C; reduction 25–80 °CStep 1: 25–80 °C; step 2: acid (or aniline·HBr), 150–200 °CDMF, 110 °C; then H₂ (1 atm), EtOAc or MeOH, 25 °C
StereochemistryNone (aromatic)NoneNone at the product; enamine is the E isomer
Rate / selectivityCondensation limited by CH acidity (pKa ≈ 20)Cyclisation (high T) is slow; SN2 alkylation is fastCondensation is slow but drives off MeOH; cyclization is fast

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Reissert indole synthesis?

o-Nitrotoluene, (CO₂Et)₂, KOEt; then Zn/AcOH (or H₂, Pd/C). Conditions: EtOH/Et₂O, 25 °C; reduction 25–80 °C.

Which bonds are formed and which are broken?

Formed: C–C (Claisen); N–H₂; C=N then C=C–N (indole ring). Broken: benzylic C–H; N–O (×2); C=O.

What is the stereochemical outcome?

None (aromatic)

What controls the rate or the selectivity?

Condensation limited by CH acidity (pKa ≈ 20)

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