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Zinc-mediated carbonyl addition

Reformatsky reaction

How the Reformatsky reaction works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: α-Bromo ester, Zn (activated), aldehyde or ketone; then H₃O⁺. Conditions: THF or benzene/Et₂O, 40–80 °C. Bonds formed: C–Zn; C–C; O–Zn → C–OH; bonds broken: C–Br; C=O π. Stereochemistry: Chair TS; modest syn/anti selectivity. Rate and selectivity: Zn insertion (needs activation) is the slow step.

At a glance

Reagentsα-Bromo ester, Zn (activated), aldehyde or ketone; then H₃O⁺
Solvent / conditionsTHF or benzene/Et₂O, 40–80 °C
Bonds formedC–Zn; C–C; O–Zn → C–OH
Bonds brokenC–Br; C=O π
StereochemistryChair TS; modest syn/anti selectivity
Rate / selectivityZn insertion (needs activation) is the slow step

Step 1: Zn inserts into C–Br

+oxidative insertionZn(0)BrOOZnBrOO1 · ZN INSERTS INTO C–BRzincREDUCTANTethyl bromoacetateC₄H₇BrO₂SUBSTRATEorganozinc (Reformatsky reagent)C₄H₇BrO₂ZnNUCLEOPHILEZinc enolates are far less basic than Li/Mg enolates, so esters survive.

Zinc metal inserts into the carbon-halogen bond of an α-halo ester, generating an organozinc reagent — milder and more functional-group-tolerant than a lithium or magnesium enolate equivalent.

Step 2: Zinc enolate adds to the carbonyl

+chair TSOOZnBrROROZnBrOO2 · ZINC ENOLATE ADDS TO THE CARBONYLzinc enolate (O-bound form)C₄H₇BrO₂ZnENOLATEaldehydeELECTROPHILEzinc alkoxideINTERMEDIATEZn bridges the enolate O and the carbonyl O in a six-membered chelate.

This zinc enolate adds to an aldehyde or ketone's carbonyl carbon through a chelated transition state, exactly paralleling the Grignard mechanism but with zinc's reduced basicity avoiding competing enolization of the substrate itself.

Step 3: Aqueous workup

H₃O⁺+ROZnBrOOROHOOZn23 · AQUEOUS WORKUPzinc alkoxideINTERMEDIATEβ-hydroxy esterPRODUCTZn²⁺ saltsBYPRODUCTNet: an ester-enolate aldol under non-basic conditions.

Aqueous workup gives a β-hydroxy ester — this reaction lets chemists perform an effective 'ester enolate aldol addition' on substrates too base-sensitive to survive a conventional strong-base-generated enolate.

Abbreviations and terms

R
R group. Any carbon substituent (alkyl, aryl…) whose identity does not matter for the mechanism.
THF
Tetrahydrofuran. Cyclic ether solvent; its oxygen lone pairs solvate Li⁺/Mg²⁺ so organometallics stay dissolved and reactive.
Et2O
Diethyl ether. Low-boiling ether solvent, classic for Grignard reagents.
TS
Transition state. The highest-energy point on the pathway between two minima; it cannot be isolated.

How it compares with related reactions

Reformatsky reactionAcid-catalyzed hydration of an alkeneBr₂ addition to an alkene (vicinal dihalide)
Reagentsα-Bromo ester, Zn (activated), aldehyde or ketone; then H₃O⁺Dilute H₂SO₄ or H₃PO₄ (H₃O⁺), H₂OBr₂
ConditionsTHF or benzene/Et₂O, 40–80 °C25–100 °C; heat and excess water favour the alcoholCH₂Cl₂ or CCl₄, 25 °C, dark
StereochemistryChair TS; modest syn/anti selectivityPlanar carbocation: racemic; Markovnikov regiochemistryAnti addition via bromonium; trans product (racemic)
Rate / selectivityZn insertion (needs activation) is the slow stepProtonation of the alkene is rate-determiningBromonium formation rate-limiting; fast

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Reformatsky reaction?

α-Bromo ester, Zn (activated), aldehyde or ketone; then H₃O⁺. Conditions: THF or benzene/Et₂O, 40–80 °C.

Which bonds are formed and which are broken?

Formed: C–Zn; C–C; O–Zn → C–OH. Broken: C–Br; C=O π.

What is the stereochemical outcome?

Chair TS; modest syn/anti selectivity

What controls the rate or the selectivity?

Zn insertion (needs activation) is the slow step

Study guides that help with this reaction

Related mechanisms

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