Mechanism Lab Open the app

Oxonium alkylation

Meerwein's salt alkylation

How the Meerwein's salt alkylation works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

Open the interactive version

In short. A 3-step mechanism. Typical reagents: Et₃O⁺ BF₄⁻ (Meerwein salt). Conditions: CH₂Cl₂, 0–25 °C, anhydrous. Bonds formed: Nu–CH₂CH₃ bond; Et₂O; bonds broken: C–O⁺ (oxonium) bond. Stereochemistry: Inversion at carbon (SN2) — invisible for ethyl. Rate and selectivity: Very fast; excellent leaving group (neutral ether).

At a glance

ReagentsEt₃O⁺ BF₄⁻ (Meerwein salt)
Solvent / conditionsCH₂Cl₂, 0–25 °C, anhydrous
Bonds formedNu–CH₂CH₃ bond; Et₂O
Bonds brokenC–O⁺ (oxonium) bond
StereochemistryInversion at carbon (SN2) — invisible for ethyl
Rate / selectivityVery fast; excellent leaving group (neutral ether)

Step 1: A stable but potent ethyl donor

+Oδ⁺FBFFF1 · A STABLE BUT POTENT ETHYL DONORtriethyloxoniumC₆H₁₅O⁺ELECTROPHILEtetrafluoroborateBYPRODUCTelectrophilic CH₂(+O leaving group)Non-nucleophilic BF₄⁻ lets the oxonium be isolated as a salt.

Triethyloxonium tetrafluoroborate (Meerwein's salt) is a stable, isolable trialkyloxonium alkylating agent — its ethyl groups are activated toward transfer by the highly stable, neutral diethyl ether byproduct that departure will form.

Step 2: SN2 by a weak nucleophile

+ONO2 · SN2 BY A WEAK NUCLEOPHILEN,N-dimethylacetamideC₄H₉NONUCLEOPHILEtriethyloxoniumC₆H₁₅O⁺ELECTROPHILEattackAmide O is far too weak to displace a halide.

A weak nucleophile — even one far too poor to displace an ordinary halide, like an amide oxygen or a pyridine nitrogen — attacks one of the electrophilic ethyl carbons directly, in a straightforward SN2 displacement.

Step 3: Alkylated cation + diethyl ether

++ONOFBFFF3 · ALKYLATED CATION + DIETHYL ETHERO-ethyl imidate cationC₆H₁₄NO⁺PRODUCTdiethyl etherC₄H₁₀OBYPRODUCTtetrafluoroborateBYPRODUCTActivated imidate: now electrophilic at carbon.

Loss of neutral diethyl ether gives the alkylated product, often as a new, more reactive cationic species (like an activated imidate from an amide) — because Meerwein's salt is such an aggressive alkylating agent, it can functionalize nucleophiles that no ordinary alkyl halide or sulfonate ester would touch.

Abbreviations and terms

Nu
Nucleophile. An electron-rich species that donates an electron pair to form a new bond.
Et2O
Diethyl ether. Low-boiling ether solvent, classic for Grignard reagents.
DCM
Dichloromethane. Common non-polar-ish solvent for reactions that need no nucleophilic or protic solvent.
SN2
Bimolecular nucleophilic substitution. One concerted step with backside attack and inversion; rate = k[RX][Nu].

How it compares with related reactions

Meerwein's salt alkylationDelépine reactionStork enamine alkylation
ReagentsEt₃O⁺ BF₄⁻ (Meerwein salt)Hexamethylenetetramine (HMTA), then HCl/EtOH (or H₃O⁺)Pyrrolidine, cat. TsOH, then R–X (or Michael acceptor), then H₃O⁺
ConditionsCH₂Cl₂, 0–25 °C, anhydrousCHCl₃ or EtOH, reflux; then ethanolic HClToluene, Dean–Stark, then CH₃CN, reflux; aqueous acid
StereochemistryInversion at carbon (SN2) — invisible for ethylInversion at a stereogenic primary/benzylic carbon (SN2)Less substituted enamine favoured; monoalkylation
Rate / selectivityVery fast; excellent leaving group (neutral ether)SN2 step rate-limiting; works for benzylic, allylic, α-halo carbonylsAlkylation (SN2) is rate-limiting; reactive halides (allylic, benzylic, α-halo carbonyl) work best

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Meerwein's salt alkylation?

Et₃O⁺ BF₄⁻ (Meerwein salt). Conditions: CH₂Cl₂, 0–25 °C, anhydrous.

Which bonds are formed and which are broken?

Formed: Nu–CH₂CH₃ bond; Et₂O. Broken: C–O⁺ (oxonium) bond.

What is the stereochemical outcome?

Inversion at carbon (SN2) — invisible for ethyl

What controls the rate or the selectivity?

Very fast; excellent leaving group (neutral ether)

Study guides that help with this reaction

Related mechanisms

Step through it interactively, then test yourself in Quiz