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α-Halogenation of carboxylic acids

Hell-Volhard-Zelinsky reaction

How the Hell-Volhard-Zelinsky reaction works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: 1) PBr₃ (or cat. P), Br₂ 2) H₂O. Conditions: Neat or CCl₄, 80–100 °C; then aqueous workup. Bonds formed: C–Br (α); acyl bromide then COOH; bonds broken: α C–H; acid C–OH. Stereochemistry: Racemic at a new α stereocentre. Rate and selectivity: Enolization of acyl bromide is rate-limiting.

At a glance

Reagents1) PBr₃ (or cat. P), Br₂ 2) H₂O
Solvent / conditionsNeat or CCl₄, 80–100 °C; then aqueous workup
Bonds formedC–Br (α); acyl bromide then COOH
Bonds brokenα C–H; acid C–OH
StereochemistryRacemic at a new α stereocentre
Rate / selectivityEnolization of acyl bromide is rate-limiting

Step 1: Acid → acyl bromide

++ROOHBrPBrBrROBrOHPOHOH1 · ACID → ACYL BROMIDEcarboxylic acidSUBSTRATEphosphorus tribromideBr₃PREAGENTacyl bromideINTERMEDIATEphosphorous acidH₃O₃PBYPRODUCTNet: –OH replaced by –Br; acyl bromides enolize far more easily than acids.

PBr₃ (or catalytic P with Br₂) converts the carboxylic acid into an acyl bromide. Unlike a free acid, an acyl bromide enolizes readily, which is the whole reason this reaction needs phosphorus.

Step 2: Enol attacks Br₂

tautomerizecat. H⁺++ROBrROHBrROHBrBrBrRBrOBrBrH2 · ENOL ATTACKS BR₂acyl bromideSUBSTRATEenolNUCLEOPHILEenolNUCLEOPHILEbromineBr₂ELECTROPHILEα-bromo acyl bromideINTERMEDIATEHBrBrHBYPRODUCTSame enol + Br₂ logic as acid-catalysed α-bromination of ketones.

The acyl bromide tautomerizes to its enol, and the enol's C=C attacks Br₂ at the α-carbon, giving an α-bromo acyl bromide — the same enol-plus-electrophilic-halogen logic as acid-catalyzed α-halogenation of a ketone.

Step 3: Hydrolysis to the α-bromo acid

++OH₂RBrOBrRBrOOHBrH3 · HYDROLYSIS TO THE Α-BROMO ACIDwaterH₂ONUCLEOPHILEα-bromo acyl bromideELECTROPHILEα-bromo carboxylic acidPRODUCTHBrBrHBYPRODUCTAddition then loss of Br⁻ (tetrahedral intermediate); α-Br then allows SN2 to amino or hydroxy acids.

Aqueous workup hydrolyzes the acyl bromide back to the carboxylic acid (or exchanges with another acid, which regenerates fresh acyl bromide), leaving the α-bromo acid. The α-bromide can then be displaced to make α-amino and α-hydroxy acids.

Abbreviations and terms

R
R group. Any carbon substituent (alkyl, aryl…) whose identity does not matter for the mechanism.
H2
Hydrogen gas. Reductant for catalytic hydrogenation.
PBr3
Phosphorus tribromide. Converts alcohols to bromides by SN2.
HBr
Hydrobromic acid. Strong acid; bromide is a good nucleophile.
SN2
Bimolecular nucleophilic substitution. One concerted step with backside attack and inversion; rate = k[RX][Nu].

How it compares with related reactions

Hell-Volhard-Zelinsky reactionAcid-catalyzed hydrolysis of a nitrileHaloform reaction of a methyl ketone
Reagents1) PBr₃ (or cat. P), Br₂ 2) H₂ONitrile R–C≡N, H₃O⁺ (conc. HCl or H₂SO₄), H₂OI₂ (or Br₂, Cl₂, NaOCl) and NaOH
ConditionsNeat or CCl₄, 80–100 °C; then aqueous workupReflux, several hoursAqueous base, 25 °C; excess halogen
StereochemistryRacemic at a new α stereocentreNo new stereocentre; α-stereocentres retainedNo stereocentre formed
Rate / selectivityEnolization of acyl bromide is rate-limitingWater attack on the protonated nitrile is rate-limiting; amide hydrolysis is the slower, forcing stageEach halogenation faster than the last (acidity increases)

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Hell-Volhard-Zelinsky reaction?

1) PBr₃ (or cat. P), Br₂ 2) H₂O. Conditions: Neat or CCl₄, 80–100 °C; then aqueous workup.

Which bonds are formed and which are broken?

Formed: C–Br (α); acyl bromide then COOH. Broken: α C–H; acid C–OH.

What is the stereochemical outcome?

Racemic at a new α stereocentre

What controls the rate or the selectivity?

Enolization of acyl bromide is rate-limiting

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