Mechanism Lab Open the app

Biosynthesis — heme radical rebound

Cytochrome P450: C–H hydroxylation

How the Cytochrome P450 works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

Open the interactive version

In short. A 3-step mechanism. Typical reagents: Cytochrome P450 (heme-thiolate), O₂, NADPH (2 e⁻ via reductase), 2 H⁺, substrate R–H. Conditions: Aqueous, pH ~7.4, 37 °C, membrane-bound or soluble enzyme. Bonds formed: C–OH; H₂O; bonds broken: C–H; O=O. Stereochemistry: Rebound is fast, so configuration is often largely retained. Rate and selectivity: Compound I formation fast; C–H abstraction is rate-limiting.

At a glance

ReagentsCytochrome P450 (heme-thiolate), O₂, NADPH (2 e⁻ via reductase), 2 H⁺, substrate R–H
Solvent / conditionsAqueous, pH ~7.4, 37 °C, membrane-bound or soluble enzyme
Bonds formedC–OH; H₂O
Bonds brokenC–H; O=O
StereochemistryRebound is fast, so configuration is often largely retained
Rate / selectivityCompound I formation fast; C–H abstraction is rate-limiting

Step 1: O₂ binding and Compound I formation

+e⁻ ; e⁻, H⁺++CysSFe(III)PorOOCysSFe(III)PorOOHCysSFe(III)PorOOHHCysSFe(IV)Por•⁺OOH₂1 · O₂ BINDING AND COMPOUND I FORMATIONP450 resting stateCATALYSTdioxygenO₂OXIDANTFe(III)–OOHINTERMEDIATEFe(III)–OOHINTERMEDIATEprotonH⁺ACIDCompound IOXIDANTwaterH₂OBYPRODUCTHeterolytic O–O cleavage: Fe(IV)=O with a porphyrin radical cation.

A heme-bound iron(III) center is reduced and binds O₂; after a second electron transfer and protonation, the O–O bond heterolyzes, releasing water and generating a highly reactive, high-valent iron(IV)-oxo porphyrin radical cation known as Compound I.

Step 2: Hydrogen-atom abstraction

++CysSFe(IV)PorOHCysSFe(IV)PorOH2 · HYDROGEN-ATOM ABSTRACTIONCompound IOXIDANTsubstrate R–HC₆H₁₂SUBSTRATEFe(IV)–OHINTERMEDIATEcarbon radicalC₆H₁₁RADICALO–H bond forms (BDE ~ 90 kcal/mol), C–H cleaves.

Compound I abstracts a hydrogen atom directly from an unactivated substrate C–H bond, generating a carbon radical and an iron(IV)-hydroxo species — an enzymatic hydrogen-atom-abstraction step conceptually parallel to the initiation step of radical halogenation, just performed by a metal-oxo instead of a halogen radical.

Step 3: Radical rebound

++CysSFe(IV)PorOHOHCysSFe(III)Por3 · RADICAL REBOUNDFe(IV)–OHINTERMEDIATEcarbon radicalC₆H₁₁RADICALalcohol productC₆H₁₂OPRODUCTresting state regeneratedCATALYSTThe OH is transferred to carbon; Fe(IV) is reduced to Fe(III).

The carbon radical rapidly recombines with the iron-bound hydroxyl (radical rebound) to install the new C–OH bond and regenerate the resting iron(III) state — this is how the human body hydroxylates otherwise completely unreactive C–H bonds in drug metabolism and steroid biosynthesis.

Abbreviations and terms

R
R group. Any carbon substituent (alkyl, aryl…) whose identity does not matter for the mechanism.
H2
Hydrogen gas. Reductant for catalytic hydrogenation.
NADP
NADP⁺ / NADPH. Phosphorylated NAD cousin used mainly in biosynthetic reductions.

How it compares with related reactions

Cytochrome P450Vitamin B12-dependent radical rearrangementDNA glycosylase
ReagentsCytochrome P450 (heme-thiolate), O₂, NADPH (2 e⁻ via reductase), 2 H⁺, substrate R–HAdenosylcobalamin (AdoCbl) cofactor; methylmalonyl-CoA mutase; substrate methylmalonyl-CoADNA glycosylase (e.g. uracil-DNA glycosylase), H₂O
ConditionsAqueous, pH ~7.4, 37 °C, membrane-bound or soluble enzymeAqueous, pH ~7, 37 °C, enzyme active sitePhysiological pH, 37 °C
StereochemistryRebound is fast, so configuration is often largely retainedStereospecific 1,2-acyl shift inside the enzymeInversion or retention at C1′ depending on enzyme
Rate / selectivityCompound I formation fast; C–H abstraction is rate-limitingSubstrate binding triggers Co–C homolysis (~10¹² acceleration)Base flipping and oxocarbenium-like TS control rate

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Cytochrome P450?

Cytochrome P450 (heme-thiolate), O₂, NADPH (2 e⁻ via reductase), 2 H⁺, substrate R–H. Conditions: Aqueous, pH ~7.4, 37 °C, membrane-bound or soluble enzyme.

Which bonds are formed and which are broken?

Formed: C–OH; H₂O. Broken: C–H; O=O.

What is the stereochemical outcome?

Rebound is fast, so configuration is often largely retained

What controls the rate or the selectivity?

Compound I formation fast; C–H abstraction is rate-limiting

Study guides that help with this reaction

Related mechanisms

Step through it interactively, then test yourself in Quiz