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Syn elimination via thionocarbonate

Corey-Winter olefination

How the Corey-Winter olefination works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: 1) TCDI (thiocarbonyldiimidazole) 2) P(OMe)₃. Conditions: Toluene or neat, 60–110 °C. Bonds formed: C=C; CO₂; (MeO)₃P=S; bonds broken: two C–O bonds; C=S π. Stereochemistry: Stereospecific syn elimination: cis-diol gives cis-alkene (suprafacial). Rate and selectivity: Driven by strong P=S and C=O (CO₂) bonds.

At a glance

Reagents1) TCDI (thiocarbonyldiimidazole) 2) P(OMe)₃
Solvent / conditionsToluene or neat, 60–110 °C
Bonds formedC=C; CO₂; (MeO)₃P=S
Bonds brokentwo C–O bonds; C=S π
StereochemistryStereospecific syn elimination: cis-diol gives cis-alkene (suprafacial)
Rate / selectivityDriven by strong P=S and C=O (CO₂) bonds

Step 1: Diol → cyclic thionocarbonate

+−2 imidazoleOHOHSNNNNSOO1 · DIOL → CYCLIC THIONOCARBONATEmeso-2,3-butanediolC₄H₁₀O₂SUBSTRATETCDIC₇H₆N₄SREAGENTcyclic thionocarbonateC₅H₈O₂SINTERMEDIATEBoth oxygens are locked into a five-membered ring.

A 1,2-diol condenses with thiocarbonyldiimidazole to form a cyclic thionocarbonate, locking both oxygens into a five-membered ring bridging the two carbons.

Step 2: Phosphite attacks sulfur

+POOOSOOδ⁻POOOSOO2 · PHOSPHITE ATTACKS SULFURtrimethyl phosphiteC₃H₉O₃PNUCLEOPHILEcyclic thionocarbonateC₅H₈O₂SELECTROPHILEphosphonium zwitterionC₈H₁₇O₅PSINTERMEDIATEPhosphorus is thiophilic: the strong P–S bond drives the step.

Treatment with a phosphine (like P(OMe)₃) attacks the thionocarbonate's sulfur, and a cascade of electron flow — sulfur transferring to phosphorus, the ring fragmenting, and CO₂ being extruded — happens in a single concerted retro-cheletropic step.

Step 3: Fragmentation: C=C forms, CO₂ leaves

−(MeO)₃P=Sretro-cheletropic(syn)++POOOSOOOOOOOOSPOOO3 · FRAGMENTATION: C=C FORMS, CO₂ LEAVESzwitterionINTERMEDIATEdioxolanylidene carbeneC₅H₈O₂CARBENEcarbeneCARBENEcis-2-buteneC₄H₈PRODUCTcarbon dioxideCO₂BYPRODUCT(MeO)₃P=SC₃H₉O₃PSBYPRODUCTBoth C–O bonds break as the π bond forms: no carbocation, no stereo-scrambling.

Both C–O bonds break simultaneously as the new C=C π bond forms, giving the alkene with clean syn stereospecificity and no carbocation intermediate — a gentle way to convert a 1,2-diol directly into an alkene under conditions mild enough for sensitive substrates.

Abbreviations and terms

OMe
Methoxy. –OCH₃.

How it compares with related reactions

Corey-Winter olefinationAldol condensationCope elimination
Reagents1) TCDI (thiocarbonyldiimidazole) 2) P(OMe)₃NaOH or KOH (cat.)H₂O₂ or mCPBA (oxidation); then heat
ConditionsToluene or neat, 60–110 °CH₂O/EtOH, heat 50–100 °COxidation 0–25 °C; elimination 80–160 °C (milder in DMSO/THF)
StereochemistryStereospecific syn elimination: cis-diol gives cis-alkene (suprafacial)Mostly E-enal (thermodynamic)Syn elimination via planar 5-membered TS
Rate / selectivityDriven by strong P=S and C=O (CO₂) bondsE1cB; loss of HO⁻ from the enolate is rate-determiningIntramolecular, first order; faster in polar aprotic solvents

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Corey-Winter olefination?

1) TCDI (thiocarbonyldiimidazole) 2) P(OMe)₃. Conditions: Toluene or neat, 60–110 °C.

Which bonds are formed and which are broken?

Formed: C=C; CO₂; (MeO)₃P=S. Broken: two C–O bonds; C=S π.

What is the stereochemical outcome?

Stereospecific syn elimination: cis-diol gives cis-alkene (suprafacial)

What controls the rate or the selectivity?

Driven by strong P=S and C=O (CO₂) bonds

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