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Radical chain — deoxygenation

Barton-McCombie deoxygenation

How the Barton-McCombie deoxygenation works, in 3 steps. Each step shows the structures and the curved arrows that move the electrons.

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In short. A 3-step mechanism. Typical reagents: 1) NaH, CS₂, CH₃I 2) Bu₃SnH, AIBN (or (TMS)₃SiH). Conditions: Toluene, 80–110 °C, radical chain. Bonds formed: C–H; C=O (S-stannyl dithiocarbonate); bonds broken: C–O; Sn–H. Stereochemistry: Stereocentre lost (planar radical). Rate and selectivity: Driven by strong C=O/Sn–S bonds; chain propagation.

At a glance

Reagents1) NaH, CS₂, CH₃I 2) Bu₃SnH, AIBN (or (TMS)₃SiH)
Solvent / conditionsToluene, 80–110 °C, radical chain
Bonds formedC–H; C=O (S-stannyl dithiocarbonate)
Bonds brokenC–O; Sn–H
StereochemistryStereocentre lost (planar radical)
Rate / selectivityDriven by strong C=O/Sn–S bonds; chain propagation

Step 1: Alcohol → xanthate

NaH, CS₂then CH₃ITHFOHOSS1 · ALCOHOL → XANTHATEcyclohexanolC₆H₁₂OSUBSTRATEmethyl xanthateC₈H₁₄OS₂INTERMEDIATEThe C=S group is a radical acceptor; a plain C–OH is not.

An alcohol is first converted to a xanthate ester (via CS₂ and methyl iodide) — this installs a C=S group that radicals add to easily, unlike a plain C–OH.

Step 2: Sn• adds to S, C–O fragments

+β-scission+Bu₃Sn•OSSOSSBu₃SnOSSSn2 · SN• ADDS TO S, C–O FRAGMENTSadduct radicalC₈H₁₄OS₂SnRADICALcyclohexyl radicalC₆H₁₁RADICALS-stannyl dithiocarbonateBYPRODUCTtributyltin radicalxanthateStrong C=O π bond formation drives expulsion of the alkyl radical.

A tin or silicon radical (from Bu₃SnH or (TMS)₃SiH, generated by a radical initiator) adds to the xanthate's sulfur, and the resulting radical fragments, expelling a stable carbon radical at the original alcohol position.

Step 3: H-atom transfer, chain continues

++HBu₃SnHBu₃Sn•3 · H-ATOM TRANSFER, CHAIN CONTINUEScyclohexyl radicalC₆H₁₁RADICALtributyltin hydrideREDUCTANTcyclohexaneC₆H₁₂PRODUCTBu₃Sn•RADICALBu₃Sn• re-enters step 2: a chain reaction.

That carbon radical abstracts a hydrogen atom from another equivalent of the tin or silicon hydride, giving the fully deoxygenated C–H product and continuing the radical chain.

Abbreviations and terms

TMS
Trimethylsilyl. –Si(CH₃)₃; a small silicon group used to protect or activate.
THF
Tetrahydrofuran. Cyclic ether solvent; its oxygen lone pairs solvate Li⁺/Mg²⁺ so organometallics stay dissolved and reactive.
NaH
Sodium hydride. Insoluble, irreversible base: removes H⁺ and bubbles off H₂.
Bu3SnH
Tributyltin hydride. Radical H-atom donor (weak Sn–H bond).
AIBN
Azobisisobutyronitrile. Radical initiator: on heating releases N₂ and two 2-cyano-2-propyl radicals.

How it compares with related reactions

Barton-McCombie deoxygenationKharasch addition (peroxide-mediated HBr addition)Radical hydrostannylation (Bu₃SnH reduction)
Reagents1) NaH, CS₂, CH₃I 2) Bu₃SnH, AIBN (or (TMS)₃SiH)HBr, ROOR (peroxide initiator) or light, alkeneBu₃SnH (cat. or stoich.), AIBN, alkyl bromide/iodide
ConditionsToluene, 80–110 °C, radical chainHeat or hν, non-polar solventBenzene or toluene, 80 °C (AIBN thermolysis)
StereochemistryStereocentre lost (planar radical)Anti-Markovnikov; radical chainRadical is planar; stereocentre lost
Rate / selectivityDriven by strong C=O/Sn–S bonds; chain propagationChain propagation; H-abstraction from HBr is fastChain propagation; Sn–Br bond strength drives halogen abstraction

Test yourself

Try to answer each question before opening it.

Which reagents and conditions are typical for the Barton-McCombie deoxygenation?

1) NaH, CS₂, CH₃I 2) Bu₃SnH, AIBN (or (TMS)₃SiH). Conditions: Toluene, 80–110 °C, radical chain.

Which bonds are formed and which are broken?

Formed: C–H; C=O (S-stannyl dithiocarbonate). Broken: C–O; Sn–H.

What is the stereochemical outcome?

Stereocentre lost (planar radical)

What controls the rate or the selectivity?

Driven by strong C=O/Sn–S bonds; chain propagation

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